29. You dissolve 280 g of sucrose (table sugar), C12H22O11(s), in 2.00 L of water.
b. Determine the number of moles of sugar in this solution.
e. Calculate the molar concentration of this solution.
stuck on these two
I worked this for you below.
https://www.jiskha.com/questions/1858386/29-you-dissolve-280-g-of-sucrose-table-sugar-c12h22o11-s-in-2-00-l-of-water-b
21
To determine the number of moles of sugar in the solution and calculate its molar concentration, you can follow these steps:
Step 1: Find the molar mass of sucrose (C12H22O11).
The molar mass of C is approximately 12.01 g/mol, H is 1.01 g/mol, and O is approximately 16.00 g/mol.
So, the molar mass of C12H22O11 is:
(12.01 x 12) + (1.01 x 22) + (16.00 x 11) = 342.34 g/mol
Step 2: Calculate the number of moles of sucrose.
To find the number of moles (n), use the formula:
n = mass / molar mass
In this case, the mass is 280 g and the molar mass is 342.34 g/mol.
So,
n = 280 g / 342.34 g/mol
n ≈ 0.8189 mol
Therefore, the number of moles of sugar in the solution is approximately 0.8189 mol.
Step 3: Calculate the molar concentration of the solution.
Molar concentration is defined as the number of moles of solute divided by the volume of the solution.
The volume of the solution is given as 2.00 L.
To calculate molar concentration (C), use the formula:
C = n / V
Where n is the number of moles and V is the volume of the solution.
In this case, n is approximately 0.8189 mol and V is 2.00 L.
So,
C = 0.8189 mol / 2.00 L
C ≈ 0.4094 mol/L
Therefore, the molar concentration of the solution is approximately 0.4094 mol/L.