calculate the [H3O+] if
pH= 2.9
pH = -log(H3O^+)
Are you stuck on how to do this?
yes
On your calculator punch the 10^x key. Then enter -2.9. Up comes the answer of 1.25E-3 M. or 1.25 x 10^-3 M
You are taking the antilog of 2.9. To check that you have done this right, punch in the log key, then 1.25 x 10^-3 and enter. You should get -2.90, then change the sign to +.
To calculate the concentration of H3O+ ions ([H3O+]) given the pH value, you can use the equation:
pH = -log[H3O+]
Rearranging the equation, we get:
[H3O+] = 10^(-pH)
Now, substitute the given pH value into the equation:
[H3O+] = 10^(-2.9)
Calculating this:
[H3O+] = 1.26 x 10^(-3) M
Therefore, the concentration of H3O+ ions is 1.26 x 10^(-3) M.