Calculate the total number of moles of gas produced from the decomposition of 10.0 g of guanidinium nitrate
I know that the equation for the decomposition is CH6N4O3 (s) → 3 H2O (g) + 2 N2 (g) + C but I don't know where to go from here.
figure the moles of CH6N4O3 in 10.0g
The equation says that you will get 5 times that many moles of gas (3H2O and 2N2)
To calculate the total number of moles of gas produced from the decomposition of guanidinium nitrate, we need to convert the given mass of guanidinium nitrate (10.0 g) into moles using its molar mass.
The molar mass of guanidinium nitrate (CH6N4O3) can be calculated by summing the individual atomic masses of its elements.
The atomic masses are as follows:
Carbon (C) = 12.01 g/mol
Hydrogen (H) = 1.01 g/mol
Nitrogen (N) = 14.01 g/mol
Oxygen (O) = 16.00 g/mol
Now, let's calculate the molar mass of guanidinium nitrate:
Molar mass of CH6N4O3 = (12.01 g/mol × 1) + (1.01 g/mol × 6) + (14.01 g/mol × 4) + (16.00 g/mol × 3)
= 12.01 g/mol + 6.06 g/mol + 56.04 g/mol + 48.00 g/mol
= 122.11 g/mol
Next, we can use the molar mass to convert the given mass of guanidinium nitrate into moles:
Moles of guanidinium nitrate = Mass of guanidinium nitrate / Molar mass of guanidinium nitrate
= 10.0 g / 122.11 g/mol
Now that we have the number of moles of guanidinium nitrate, we can use the coefficients in the balanced equation to determine the molar ratios between guanidinium nitrate and the gases produced.
From the balanced equation, we see that:
1 mole of CH6N4O3 produces 3 moles of H2O
1 mole of CH6N4O3 produces 2 moles of N2
Finally, we can calculate the total number of moles of gas produced by multiplying the moles of guanidinium nitrate by the respective molar ratios:
Moles of H2O = Moles of guanidinium nitrate × 3
Moles of N2 = Moles of guanidinium nitrate × 2
Therefore, to find the total number of moles of gas produced, we can sum the moles of H2O and N2.
I hope this helps! Let me know if you need further assistance.
mol of CH6N4O3 is 12+6+(4*14)+(3*16) grams
Well, let's break it down!
First, let's find the molar mass of guanidinium nitrate (CH6N4O3):
- Carbon (C) has a molar mass of approximately 12 g/mol
- Hydrogen (H) has a molar mass of approximately 1 g/mol
- Nitrogen (N) has a molar mass of approximately 14 g/mol
- Oxygen (O) has a molar mass of approximately 16 g/mol
So, the molar mass of guanidinium nitrate is:
(1 * 12 g/mol) + (6 * 1 g/mol) + (4 * 14 g/mol) + (3 * 16 g/mol) = 84 g/mol
Now, let's calculate the number of moles of guanidinium nitrate in 10.0 g:
Number of moles = mass (g) / molar mass (g/mol) = 10.0 g / 84 g/mol ≈ 0.119 moles
According to the balanced chemical equation, 1 mole of guanidinium nitrate produces 2 moles of nitrogen gas (N2). So, 0.119 moles of guanidinium nitrate will produce 0.119 moles * 2 = 0.238 moles of nitrogen gas.
Therefore, the total number of moles of gas produced from the decomposition of 10.0 g of guanidinium nitrate is approximately 0.238 moles.
To calculate the total number of moles of gas produced from the decomposition of guanidinium nitrate (CH6N4O3), you need to consider the balanced equation and use the concept of stoichiometry.
Step 1: Write down the balanced equation:
CH6N4O3 (s) → 3 H2O (g) + 2 N2 (g) + C
Step 2: Calculate the molar mass of guanidinium nitrate (CH6N4O3):
C: 12.01 g/mol
H: 1.008 g/mol (6 hydrogens)
N: 14.01 g/mol (4 nitrogens)
O: 16.00 g/mol (3 oxygens)
Molar mass of CH6N4O3 = (12.01 * 1) + (1.008 * 6) + (14.01 * 4) + (16.00 * 3) = 86.07 g/mol
Step 3: Convert the given mass of guanidinium nitrate to moles:
Given mass = 10.0 g
Molar mass = 86.07 g/mol
Number of moles = Given mass / Molar mass = 10.0 g / 86.07 g/mol = 0.116 mol
Step 4: Use the stoichiometry of the balanced equation to determine the moles of the gases produced:
From the balanced equation, you can see that for every 1 mole of guanidinium nitrate, 3 moles of water vapor (H2O) and 2 moles of nitrogen gas (N2) are produced.
Therefore, for 0.116 moles of guanidinium nitrate:
- 3 moles of water vapor (H2O) are produced.
- 2 moles of nitrogen gas (N2) are produced.
Total moles of gas produced = 3 + 2 = 5 moles
So, the total number of moles of gas produced from the decomposition of 10.0 g of guanidinium nitrate is 5 moles.