A roller coaster’s velocity at the top of a hill is 10m/s. Two seconds later it reaches the bottom of the hill with a velocity of 26m/s. What is the acceleration of the roller coaster?

a = ∆v/∆t = (26-10)m/s / 2s = 8 m/s^2

pretty steep hill, since falling straight down, g = 9.8 m/s^2

To find the acceleration of the roller coaster, we can use the formula:

acceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 26 m/s
Time (t) = 2 seconds

Substituting the values into the formula:
acceleration = (26 m/s - 10 m/s) / 2 s

Simplifying the expression:
acceleration = 16 m/s / 2 s
acceleration = 8 m/s²

Therefore, the acceleration of the roller coaster is 8 m/s².

To find the acceleration of the roller coaster, we need to use the equation of motion:

v = u + at

where:
v = final velocity (26 m/s)
u = initial velocity (10 m/s)
a = acceleration (unknown)
t = time (2 seconds)

Rearranging the equation, we get:

a = (v - u) / t

Substituting the given values:

a = (26 - 10) / 2

Simplifying this equation:

a = 16 / 2

a = 8 m/s²

Therefore, the acceleration of the roller coaster is 8 m/s².