An irregular polygon has its exterior angles as 140,120,132,142,112and x .find the value of x
That is some crazy polygon! Some starfish gone crazy!
For any convex polygon, the exterior angles add to 360.
So, I suspect you meant that the interior angles were given above.
Since there are 6 angles, they sum to 4*180 = 720
So, to find x, solve
140+120+132+142+112+ x = 720
Yes
The sum of the exterior angles of any polygon is always 360 degrees. Therefore, you can find the value of x by subtracting the sum of the given exterior angles from 360.
Sum of given exterior angles: 140 + 120 + 132 + 142 + 112 = 646
x = 360 - 646
x = -286
Therefore, the value of x is -286.
To find the value of x in an irregular polygon, we can first use the fact that the sum of the exterior angles of any polygon is always 360 degrees.
So, the sum of the given exterior angles is:
140 + 120 + 132 + 142 + 112 + x = 360
To solve for x, we need to isolate it by subtracting the sum of the known angles from both sides of the equation:
x = 360 - (140 + 120 + 132 + 142 + 112)
x = 360 - 646
x = -286
Therefore, the value of x is -286.