Write a C program to calculate the value of x in the quadratic equation.

𝑎𝑥
2 + 𝑏𝑥
+ 𝑐 = 0
Where 𝑥 =
−𝑏±√𝑏2−4𝑎𝑐
2𝑎
Implement using the following conditions.
If 𝑏
2 − 4𝑎𝑐 = 0 then Equation has two equal values.
If 𝑏
2 − 4𝑎𝑐 > 0 then Equation has two distinct values.
If 𝑏
2 − 4𝑎𝑐 < 0 then Equation has no roots.

looks like you just need to review basic C syntax for math calculations.

There are many examples online

and, when typing online, use ^ for exponents, as in b^2, rather than
b2 or b
2

Write a C program to calculate the value of x in the quadratic equation.

𝑎𝑥
2 + 𝑏𝑥
+ 𝑐 = 0
Where 𝑥 =
−𝑏±√𝑏2−4𝑎𝑐
2𝑎
Implement using the following conditions.
If 𝑏
2 − 4𝑎𝑐 = 0 then Equation has two equal values.
If 𝑏
2 − 4𝑎𝑐 > 0 then Equation has two distinct values.
If 𝑏
2 − 4𝑎𝑐 < 0 then Equation has no roots.

Here's a step-by-step implementation of a C program to calculate the value(s) of x in a quadratic equation.

1. Start by including the necessary header files:
```c
#include <stdio.h>
#include <math.h>
```

2. Define a function `calculateRoots` that takes three parameters: a, b, and c.
```c
void calculateRoots(float a, float b, float c) {
// ... implementation of the function will go here
}
```

3. Inside the `calculateRoots` function, calculate the discriminant value using the formula `b^2 - 4ac`, and store it in a variable called `discriminant`.
```c
float discriminant = (b * b) - (4 * a * c);
```

4. Check the value of the discriminant to determine the nature of the roots.

- If the discriminant is equal to 0, the equation has two equal roots.
```c
if (discriminant == 0) {
float root = -b / (2 * a);
printf("The equation has two equal roots: %.2f\n", root);
}
```

- If the discriminant is greater than 0, the equation has two distinct roots.
```c
else if (discriminant > 0) {
float root1 = (-b + sqrt(discriminant)) / (2 * a);
float root2 = (-b - sqrt(discriminant)) / (2 * a);
printf("The equation has two distinct roots: %.2f and %.2f\n", root1, root2);
}
```

- If the discriminant is less than 0, the equation has no real roots.
```c
else {
printf("The equation has no real roots.\n");
}
```

5. Finally, write the main function to get the values of a, b, and c from the user and call the `calculateRoots` function.
```c
int main() {
float a, b, c;

printf("Enter the values of a, b, and c: ");
scanf("%f %f %f", &a, &b, &c);

calculateRoots(a, b, c);

return 0;
}
```

This is a complete implementation of a C program that calculates the value(s) of x in a quadratic equation based on the given conditions.

Sure! Here's a C program that calculates the value of x in the quadratic equation, based on the conditions you provided:

```c
#include <stdio.h>
#include <math.h>

int main() {
float a, b, c, discriminant, x1, x2;

// Get coefficients a, b, and c from the user
printf("Enter the coefficients a, b, and c: ");
scanf("%f %f %f", &a, &b, &c);

// Calculate the discriminant
discriminant = b * b - 4 * a * c;

// Check the value of the discriminant
if (discriminant == 0) {
// Two equal values
x1 = -b / (2 * a);
x2 = x1;
printf("Equation has two equal values: x = %.2f\n", x1);
} else if (discriminant > 0) {
// Two distinct values
x1 = (-b + sqrt(discriminant)) / (2 * a);
x2 = (-b - sqrt(discriminant)) / (2 * a);
printf("Equation has two distinct values: x1 = %.2f, x2 = %.2f\n", x1, x2);
} else {
// No roots
printf("Equation has no roots.\n");
}

return 0;
}
```
Let me explain the code to you:

1. First, we include the necessary header files, `stdio.h` for input/output and `math.h` for mathematical operations.

2. In the main function, we declare variables `a`, `b`, `c`, `discriminant`, `x1`, and `x2`.

3. We ask the user to enter the coefficients `a`, `b`, and `c`.

4. Next, we calculate the discriminant using the formula `b * b - 4 * a * c`.

5. We check the value of the discriminant using if-else statements.

6. If the discriminant is equal to 0, we calculate `x` using the formula `-b / (2 * a)` and display the result as two equal values.

7. If the discriminant is greater than 0, we calculate `x1` and `x2` using the quadratic formula, and display the results as two distinct values.

8. If the discriminant is less than 0, we display that the equation has no roots.

9. Finally, we return 0 to indicate successful program execution.

You can compile and run this program to calculate the value of `x` in the quadratic equation based on the given conditions.