Mr. Wood and Mr. Smith each have two children under 9 years old. Below is some information about their children.
Mike is 3 years younger than his brother.
Royston is the oldest among the four children.
Sean's age is half of Mr. Wood's child's age.
Jack is 1 year older than Mr. Smith’s younger child.
Each family had only one child three years ago.
Each child is a different age. Can you list the children’s ages and match them with their family members?
Plz help
Use excerpt from Barack Obama's First Inaugural Address to answer the question.
How does Obama describe the state of the nation in the excerpt? Explain
A. in crisis
B. hopeful
C. powerful
D. recovering
To solve this puzzle and determine the children's ages and match them with their family members, we can follow these steps:
Step 1: Identify the relationships and information given:
- Mr. Wood and Mr. Smith each have two children under 9 years old.
- Mike is 3 years younger than his brother.
- Royston is the oldest among the four children.
- Sean's age is half of Mr. Wood's child's age.
- Jack is 1 year older than Mr. Smith's younger child.
- Each family had only one child three years ago.
Step 2: Create a table to organize the information:
| | 1st Child | 2nd Child |
|----------|-----------|-----------|
| Wood | | |
| Smith | | |
Step 3: Fill in the table with initial information:
| | 1st Child | 2nd Child |
|----------|-----------|-----------|
| Wood | | |
| Smith | | |
Step 4: From the given information, we can deduce that Royston must be the oldest among the four children. Therefore, Royston belongs to one of the fathers, let's say Wood:
| | 1st Child | 2nd Child |
|----------|-----------|-----------|
| Wood | Royston | |
| Smith | | |
Step 5: From the given information, we know that each family had only one child three years ago. This means that Royston cannot be the youngest because that would mean Wood and Smith would have had no children before three years ago, which is not possible. Mike also cannot be the oldest because he is 3 years younger than his brother. Therefore, Mike must be Wood's second child:
| | 1st Child | 2nd Child |
|----------|-----------|-----------|
| Wood | Royston | Mike |
| Smith | | |
Step 6: From the given information, Jack is 1 year older than Mr. Smith's younger child. This means Jack cannot be the oldest or the youngest child. Since Royston is the oldest, Jack must be Mr. Smith's second child:
| | 1st Child | 2nd Child |
|----------|-----------|-----------|
| Wood | Royston | Mike |
| Smith | | Jack |
Step 7: From the given information, Sean's age is half of Mr. Wood's child's age. Since Royston is Wood's child, Sean must belong to Mr. Smith:
| | 1st Child | 2nd Child |
|----------|-----------|-----------|
| Wood | Royston | Mike |
| Smith | Sean | Jack |
Now, we have successfully matched the children's ages with their family members. The final answer is:
Mr. Wood's children: Royston (oldest) and Mike.
Mr. Smith's children: Sean and Jack.
You are giving to terrible information huh
0123
Answer: B. hopeful
Explanation: In the excerpt from Barack Obama's First Inaugural Address, he describes the state of the nation with words like "hopeful" and "possibility." He acknowledges the challenges the nation is facing, but also emphasizes the strength and resilience of the American people. He talks about the need to come together to address these challenges and to build a better future. Overall, his tone is one of optimism and hopefulness.
Each family had only one child three years ago.
so there are two children age 3
Mike is 3 years younger than his brother.
so Mike is 3 and his brother is 6
Royston is the oldest among the four children.
Royston > 6
see what you can do now