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Darryl had 5/6 as many pennies as David. When David gave half of his pennies to Darryl, he had 45 fewer pennies than his friend. How many pennies did David have at first?

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  1. Let David has x pennies
    then Darryl has = 5/6x
    Now, after giving half pennies to Darryl,
    David has = x/2
    Darryl has = 5x/6 + x/2 = (5x + 3x)/6 = 8x/6 = 4x/3
    So, 4x/3 - x/2 = 45 = (8x - 3x)/6 = 45 = 5x/6 = 45 => x = (45 * 6)/5 = 54
    So, David had at first = 54 pennies

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