If triangle ABC A(-1, 4), B(2, 1), C(0, -3) is translated 2 units up, what are the new coordinates for triangle A'B'C'?
You have a bunch of (x,y) pairs. Add 2 to all the y-values.
To translate a figure 2 units up, you add 2 to the y-coordinates of each point.
So, for triangle ABC:
- Point A(-1, 4) translates to A'(-1, 4+2) = A'(-1, 6)
- Point B(2, 1) translates to B'(2, 1+2) = B'(2, 3)
- Point C(0, -3) translates to C'(0, -3+2) = C'(0, -1)
Therefore, the new coordinates for triangle A'B'C' are A'(-1, 6), B'(2, 3), and C'(0, -1).
To find the new coordinates for triangle A'B'C' after it is translated 2 units up, we need to add 2 to the y-coordinate of each point in the original triangle.
Let's go through each point one by one:
1. Point A(-1, 4)
To translate this point 2 units up, we add 2 to the y-coordinate:
New coordinates for A': (-1, 4 + 2) = (-1, 6)
2. Point B(2, 1)
To translate this point 2 units up, we add 2 to the y-coordinate:
New coordinates for B': (2, 1 + 2) = (2, 3)
3. Point C(0, -3)
To translate this point 2 units up, we add 2 to the y-coordinate:
New coordinates for C': (0, -3 + 2) = (0, -1)
Therefore, the new coordinates for triangle A'B'C' are A'(-1, 6), B'(2, 3), and C'(0, -1).