The density of milk is approximately 1.03 g/mL. If you happen to spill 0.545 gallons of

milk on the floor, what mass of milk did you spill in kilograms? You must show your
work and you may only use the following conversion factors: 1 gallon = 3.78 liters, 1000
mL = 1 liter, 100 cL = 1 liter, 1 pint = 0.125 gallons, 1000 mg = 1 g, 100 cg = 1 g, 1000 g
= 1 kg)

My answer I got is 2.121 kg

My word. Why didn't you show your work. I can check your conversion factors in a jif, then check the math and be done BUT you want me to start from scratch and spend all that wasted time when I could be helping others. So

0.545 gallons milk x (3.78 L/gallon) x (1000 mL/L) = 2060.1 mL
mass = volume x density = 2060.1 mL x 1.03 g/mL = 2121.9 grams.
2121.9 grams x (1 kg/1000 g) = 2.1219 kg which I would round to 2.122 kg.
By the way, you don't get credit for this unless you show your work.

To calculate the mass of milk spilled in kilograms, we need to follow these steps:

Step 1: Convert gallons to liters.
Given: 0.545 gallons
Conversion factor: 1 gallon = 3.78 liters

0.545 gallons × 3.78 liters/gallon = 2.0611 liters

Step 2: Convert liters to milliliters.
Given: 2.0611 liters
Conversion factor: 1000 mL = 1 liter

2.0611 liters × 1000 mL/liter = 2061.1 mL

Step 3: Convert milliliters to grams.
Given: 2061.1 mL
Density of milk: 1.03 g/mL

2061.1 mL × 1.03 g/mL = 2123.833 grams

Step 4: Convert grams to kilograms.
Given: 2123.833 grams
Conversion factor: 1000 g = 1 kg

2123.833 g ÷ 1000 g/kg = 2.123833 kg

Rounded to three decimal places, the mass of milk spilled is approximately 2.124 kg.

So, it seems that your answer of 2.121 kg is close, but rounding to three decimal places gives us a more accurate answer of 2.124 kg.