The double displacement reaction of aluminum sulfate and calcium hydroxide.

what about it?

Al2(SO4)3(aq) + 3Ca(OH)2(aq) --> 3CaSO4(s) + 2Al(OH)3(s)

2Al (aq) + 3SO4 (aq) + 3Ca (aq) + 6OH (aq) --> 2Al(OH)3 (s) + 3CaSO4 (s)

Well, it seems like aluminum sulfate and calcium hydroxide walked into a chemical reaction party! And you know what happens at chemical reaction parties, right? There's some serious swapping going on!

So, aluminum sulfate (Al₂(SO₄)₃) and calcium hydroxide (Ca(OH)₂) decide to mingle and do a double displacement dance. The sulfate ion (SO₄²⁻) from aluminum sulfate decides to swap partners with the hydroxide ion (OH⁻) from calcium hydroxide. It's like a chemistry tango!

The end result is aluminum hydroxide (Al(OH)₃) and calcium sulfate (CaSO₄). They're pretty compatible, I must say. They're both solid compounds, so they'll probably settle down and live happily ever after as precipitates.

Just a friendly word of advice, though - don't try this dance move at your next party. Leave it to the chemicals!

The double displacement reaction between aluminum sulfate (Al2(SO4)3) and calcium hydroxide (Ca(OH)2) can be given as:

Al2(SO4)3 + 3Ca(OH)2 -> 2Al(OH)3 + 3CaSO4

Step 1: Write the balanced equation by using the chemical formulas of the reactants and products.

2Al(SO4)3 + 3Ca(OH)2 -> 2Al(OH)3 + 3Ca(SO4)2

Step 2: Identify the cations and anions in the reactants and products.

Reactants:
- Aluminum sulfate: Cations - Al3+, Anions - SO4^2-
- Calcium hydroxide: Cations - Ca2+, Anions - OH^-

Products:
- Aluminum hydroxide: Cations - Al3+, Anions - OH^-
- Calcium sulfate: Cations - Ca2+, Anions - SO4^2-

Step 3: Check if the cations and anions are balanced.

In the reactants, there are 2 Al3+ cations, 3 SO4^2- anions, 3 Ca2+ cations, and 6 OH^- anions.

In the products, there are 2 Al3+ cations, 6 OH^- anions, 3 Ca2+ cations, and 3 SO4^2- anions.

Step 4: Balance the equation by adjusting the coefficients in front of the chemical formulas.

2Al(SO4)3 + 3Ca(OH)2 -> 2Al(OH)3 + 3Ca(SO4)2

Now the equation is balanced with 2 Al atoms on both sides, 6 OH^- ions on both sides, 3 Ca atoms on both sides, and 6 SO4^2- ions on both sides.

This is the balanced equation for the double displacement reaction between aluminum sulfate and calcium hydroxide.

To understand the double displacement reaction between aluminum sulfate and calcium hydroxide, we first need to know the chemical formulas of these compounds.

The chemical formula for aluminum sulfate is Al2(SO4)3, where aluminum (Al) has a +3 charge and sulfate (SO4) has a -2 charge.

The chemical formula for calcium hydroxide is Ca(OH)2, where calcium (Ca) has a +2 charge and hydroxide (OH) has a -1 charge.

In a double displacement reaction, the positive ions of two compounds exchange places. In this case, the aluminum ion (Al3+) from aluminum sulfate will combine with the hydroxide ion (OH-) from calcium hydroxide, forming aluminum hydroxide (Al(OH)3):

Al2(SO4)3 + 3Ca(OH)2 -> 2Al(OH)3 + 3CaSO4

Similarly, the calcium ion (Ca2+) from calcium hydroxide will combine with the sulfate ion (SO42-) from aluminum sulfate, forming a precipitate of calcium sulfate (CaSO4):

Al2(SO4)3 + 3Ca(OH)2 -> 2Al(OH)3 + 3CaSO4

So, the product of this double displacement reaction is aluminum hydroxide (Al(OH)3) and calcium sulfate (CaSO4).