A fair spinner is in the shape of a regular hexagon. Write a number on each section so that the probability of getting an odd

number is one- third.

1,2,3,4,6,8 comes to mind ...

Joe biden

To ensure that the probability of getting an odd number is one-third, you need to distribute the numbers on the hexagon in a specific way. Here's how you can do it:

1. Start by labeling each section of the hexagon with numbers from 1 to 6.
2. To achieve a probability of one-third for odd numbers, you need to have two odd numbers and four even numbers.
3. Allocate the odd numbers (1, 3, or 5) in any two of the sections.
4. Distribute the even numbers (2, 4, or 6) in the remaining four sections.

Here's one possible arrangement:

1. Place the number 1 on one section.
2. Place the number 3 on a neighboring section.
3. Distribute the even numbers (2, 4, 6) in the remaining four sections.

Keep in mind that there are multiple configurations that can achieve the desired probability, so you can explore different arrangements within the guidelines mentioned above.

To solve this problem, we need to assign numbers to each section of the fair spinner in such a way that the probability of getting an odd number is one-third.

A regular hexagon has six equal sides, so we need to assign six numbers to the sections. Let's label the sections as follows:

A B
F C
E D

To find a solution, we can start by assigning 1, 3, and 5 to three of the sections (A, B, and C) since these are odd numbers. This way, the probability of getting an odd number from these three sections would be 3/6, which simplifies to 1/2.

To achieve a probability of one-third, we need to balance the odd numbers with even numbers. We can assign 2, 4, and 6 to the remaining sections (D, E, and F).

With this assignment, the odd numbers (1, 3, 5) have a probability of 3/6 = 1/2, and the even numbers (2, 4, 6) also have a probability of 3/6 = 1/2. Therefore, the probability of getting an odd number is indeed one-third.