A total of 210 people attended the opening night of a school musical. Student tickets cost $3.00 each while general admission tickets cost $7.50 each. If total sales were $1296, how many general admission tickets were sold?

s = number of student tickets

g = number of general admission tickets

A total of 210 people attended the opening night of a school musical means:

s + g = 210

Student tickets cost $3.00 each while general admission tickets
cost $7.50 each, total sales were $1296 means:

3 s + 7.5 g = 1296

Now you must solve system:

s + g = 210

3 s + 7.5 g = 1296

Try it.

The solution is:

s = 62

g = 148

Checking the results:

s + g = 62 + 148 = 210

3 s + 7.5 g = $3 ∙ 62 + $7.5 ∙ 148 = $186 + $1110 = $1296

Why did the scarecrow win an award? Because he was outstanding in his field!

Now, let's solve the problem. Let's assume that x represents the number of general admission tickets sold. Since the total number of people attending the musical was 210, the number of student tickets sold can be calculated as (210 - x).

Now, let's calculate the total sales from each type of ticket. The total sales from student tickets can be calculated as 3 * (210 - x), and the total sales from general admission tickets can be calculated as 7.50 * x.

Since the total sales were $1296, we can set up the equation:

3 * (210 - x) + 7.50 * x = 1296

Now, let's solve for x:

630 - 3x + 7.50x = 1296
4.50x = 666
x ≈ 148

Therefore, approximately 148 general admission tickets were sold.

Let's assume the number of general admission tickets sold is "x".

The number of student tickets sold would be the difference between the total number of tickets and the number of general admission tickets, which is 210 - x.

The total sales from student tickets would be the number of student tickets sold multiplied by the price of each student ticket, which is (210 - x) * $3.00.
Similarly, the total sales from general admission tickets would be the number of general admission tickets sold multiplied by the price of each general admission ticket, which is x * $7.50.

According to the problem, the total sales were $1296, so we can write the equation:
(210 - x) * $3.00 + x * $7.50 = $1296.

Now we can solve this equation to find the value of x, which represents the number of general admission tickets sold.
(210 - x) * $3.00 + x * $7.50 = $1296.
630 - 3x + 7.50x = $1296.
4.5x = $1296 - $630.
4.5x = $666.
x = $666 / 4.5.
x = 148.

Therefore, 148 general admission tickets were sold.

To solve this question, we can set up a system of equations. Let's assume that 'x' represents the number of student tickets sold, and 'y' represents the number of general admission tickets sold.

From the given information, we have two equations:

Equation 1: x + y = 210 (since the total number of people who attended the event is the sum of student and general admission tickets sold)

Equation 2: (3x) + (7.50y) = 1296 (since the total sales revenue is the sum of the revenue from student and general admission tickets sold)

Now, we can solve this system of equations using either the substitution or elimination method.

Let's use the substitution method:

From Equation 1, we can solve for x in terms of y:
x = 210 - y

Substitute x in Equation 2:
(3(210 - y)) + (7.50y) = 1296

Simplify:
630 - 3y + 7.50y = 1296
4.50y = 1296 - 630
4.50y = 666
y = 666 / 4.50
y ≈ 148

Therefore, approximately 148 general admission tickets were sold.