The time period in seconds, T, for a pendulum to swing is directly proportional to the square root of its length in metres. A pendulum of length 25cm takes a period of 1 second. What length will take a period of 1.2 seconds?

T = k√L so T/√L is constant.

You want L such that
1.2/√L = 1/√25

Why did the pendulum go to the doctor? Because it needed a check-up!

To solve this problem, we can use the formula for the period of a pendulum: T = k√L, where T is the period, L is the length of the pendulum, and k is a constant of proportionality.

We're given that a pendulum of length 25 cm (which is equivalent to 0.25 m) takes a period of 1 second. Let's plug those values into the formula:

1 = k√0.25

Now, let's solve for k:

k = 1 / √0.25
k = 1 / 0.5
k = 2

Now that we have the value of k, we can find the length of the pendulum that takes a period of 1.2 seconds:

1.2 = 2√L

Divide both sides by 2:

0.6 = √L

Square both sides:

0.36 = L

So, a pendulum with a length of 0.36 meters (or 36 cm) will take a period of 1.2 seconds. Just make sure you don't get tangled up in its humor!

To find the length of the pendulum that will take a period of 1.2 seconds, we can set up a proportion using the given information.

Let L be the length of the pendulum in meters, and let T be the period in seconds.

According to the given information, we have the following:

L = 0.25 meters (since the length is given as 25 cm)
T = 1 second

Using the given information, we can determine the constant of proportionality by rearranging the equation:

T = k * sqrt(L)

1 = k * sqrt(0.25)

Simplifying the equation:

1 = k * 0.5

k = 1 / 0.5

k = 2

Now, we can use the constant of proportionality to find the length of the pendulum that will take a period of 1.2 seconds:

T = 1.2 seconds (new period)

1.2 = 2 * sqrt(L)

Dividing both sides by 2:

0.6 = sqrt(L)

Squaring both sides to eliminate the square root:

0.6^2 = L

0.36 = L

Therefore, a pendulum of length 0.36 meters (or 36 cm) will take a period of 1.2 seconds.

To solve this problem, we need to use the formula provided that relates the time period and the length of the pendulum. The formula states:

T = k * sqrt(L)

Where T is the time period in seconds, L is the length of the pendulum in meters, and k is a constant of proportionality.

We are given that a pendulum with a length of 25 cm (or 0.25 meters) has a time period of 1 second. Using this information, we can substitute the values into the formula to find the value of k:

1 = k * sqrt(0.25)

Let's solve this equation for k:

sqrt(0.25) = 0.5

So, we have:

1 = k * 0.5

Dividing both sides of the equation by 0.5:

1 / 0.5 = k

k = 2

Now that we have the value of k, we can use it to find the length, L, that will result in a time period of 1.2 seconds.

T = 1.2 seconds

Using the formula:

1.2 = 2 * sqrt(L)

Dividing both sides by 2:

0.6 = sqrt(L)

Squaring both sides to eliminate the square root:

0.6^2 = L

L = 0.36 meters

Therefore, a pendulum with a length of 0.36 meters will have a time period of 1.2 seconds.