Given that log x = 5 and log y = -7. Evaluate log x/y.
So what is the answer.
To evaluate log x/y, we can use logarithmic properties.
The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator.
So, we have:
log x/y = log x - log y
Since log x = 5 and log y = -7, we can substitute these values into the equation:
log x/y = 5 - (-7)
Simplifying, we have:
log x/y = 5 + 7
Therefore, log x/y = 12.
To evaluate log x/y, we can use the property of logarithms that states:
log (a/b) = log a - log b
In this case, we have log x/y. Substituting the given values, we get:
log x/y = log x - log y
Given that log x = 5 and log y = -7, we can substitute these values into the equation:
log x/y = 5 - (-7)
Now, we can simplify the equation further:
log x/y = 5 + 7
log x/y = 12
Therefore, log x/y is equal to 12.
log x/y = logx - logy
plug in your numbers, and review the topic some more.