two point charges are located on the y axis as follows :
charge q1 = -1.50nc at y= -0.600m, and
charge q2 = +3.2nc at the origin (y=0)
what is the net force (magnitude and direction) exerted by these two charges on a third charge q3 = +5.00 nc located at y = -0.400 m
F = k Qa Qb /d^2
Like charges repel , unlike attract, so both pull down
so
F = k * (10*-9)^2 * 5 * ( -3.2/.4^2 - 1.5/ .2^2) Newtons
two point charges are located on the y axis as follows :
charge q1 = -1.50nc at y= -0.600m, and
charge q2 = +3.2nc at the origin (y=0)
what is the net force (magnitude and direction) exerted by these two charges on a third charge q3 = +5.00 nc located at y = -0.400 m
To find the net force exerted by the two charges on the third charge, we need to calculate the force between each pair of charges and then add them together.
We can use Coulomb's Law to calculate the force between two charges:
F = (k * |q1 * q2|) / r^2
where F is the force, k is the electrostatic constant (9 x 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between them.
Now let's calculate the forces between the charges:
1. Force between q1 and q3:
q1 = -1.50 nc
q3 = +5.00 nc
r1 = (-0.400 m - (-0.600 m)) = 0.200 m
F1 = (9 x 10^9 N m^2/C^2) * ((1.50 nc) * (5.00 nc)) / (0.200 m)^2
2. Force between q2 and q3:
q2 = +3.20 nc
r2 = (-0.400 m - 0 m) = -0.400 m
F2 = (9 x 10^9 N m^2/C^2) * ((3.20 nc) * (5.00 nc)) / (0.400 m)^2
Now let's calculate the net force:
Net force = F1 + F2
Note: The direction of the force will depend on the direction of the charges and their positions. The magnitude of the force will be a positive value.
Please let me know if you would like me to calculate the actual values for the net force.
To find the net force exerted by the two charges on the third charge, you can use the principle of superposition. The net force is the vector sum of the individual forces exerted by the charges q1 and q2 on charge q3.
The force between two point charges can be calculated using Coulomb's law:
F = k * |q1 * q2| / r^2
where F is the force, k is the electrostatic constant (k = 8.99 x 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
First, let's calculate the force between q1 and q3:
Distance between q1 and q3, r1 = |y3 - y1| = |-0.400 m - (-0.600 m)| = 0.200 m
Force between q1 and q3, F1 = k * |q1 * q3| / r1^2
Plugging in the values:
F1 = (8.99 x 10^9 N m^2/C^2) * |-1.50 nC * 5.00 nC| / (0.200 m)^2
Next, let's calculate the force between q2 and q3:
Distance between q2 and q3, r2 = |y3 - y2| = |-0.400 m - 0 m| = 0.400 m
Force between q2 and q3, F2 = k * |q2 * q3| / r2^2
Plugging in the values:
F2 = (8.99 x 10^9 N m^2/C^2) * |3.2 nC * 5.00 nC| / (0.400 m)^2
Now, we can find the net force by summing F1 and F2:
Net force, F_net = F1 + F2
To determine the direction of the net force, we need to consider the signs of the charges. Since q1 is negative and q3 is positive, they will exert an attractive force. Similarly, since q2 is positive and q3 is positive, they will exert a repulsive force. The direction of the net force will be determined by the stronger force.
If F1 > F2, the net force will be attractive and point towards the negative charge q1.
If F2 > F1, the net force will be repulsive and point away from the positive charge q2.
By calculating F1 and F2, you can determine the net force and its direction.