how many grams of ice at 0c could be melted by the addition of 0.400kj of heat
400 J = mass ice x heat fusion of ice
Post your work if you run into trouble.
To determine the number of grams of ice that can be melted by the addition of 0.400 kJ of heat, we need to use the equation:
q = m * ΔHf
where:
q = heat energy in joules
m = mass of the substance (in grams)
ΔHf = heat of fusion (enthalpy of fusion) in joules/gram
The heat of fusion for ice is approximately 334 J/g.
First, we convert the given value of heat energy from kilojoules to joules:
0.400 kJ = 0.400 * 1000 J = 400 J
Next, we can rearrange the equation to solve for the mass of ice:
m = q / ΔHf
Substituting the known values:
m = 400 J / 334 J/g
m ≈ 1.20 grams
Therefore, approximately 1.20 grams of ice at 0°C can be melted by the addition of 0.400 kJ of heat.
To determine how many grams of ice at 0°C can be melted by the addition of 0.400 kJ of heat, we need to use the concept of heat of fusion and the equation Q = mcΔT.
1. Determine the heat of fusion: The heat of fusion is the amount of energy required to change a substance from a solid to a liquid phase at its melting point. For ice, it is 334 J/g.
2. Convert the given heat from kJ to J: 0.400 kJ = 0.400 × 1000 = 400 J.
3. Rearrange the equation Q = mcΔT to solve for mass (m):
m = Q / (cΔT), where Q is the heat, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
Since we're dealing with ice melting, there is no change in temperature (ΔT = 0). Therefore, the equation simplifies to:
m = Q / c.
4. Calculate the mass of ice:
m = 400 J / 334 J/g = 1.20 g.
Therefore, 1.20 grams of ice at 0°C can be melted by the addition of 0.400 kJ of heat.