An object with a charge of 2.0x10-4 C creates an electric field. A test charge of +1.0x10-6 C experiences a force of 0.050 N. The electric field strength is?
5.0×10⁴ N/C
To find the electric field strength, we can use the formula:
Electric Field Strength (E) = Force (F) / Test Charge (q)
Given:
Force (F) = 0.050 N
Test Charge (q) = +1.0x10-6 C
Plugging these values into the formula, we get:
Electric Field Strength (E) = 0.050 N / (+1.0x10-6 C)
Calculating this, we find:
E = 5.0x10^4 N/C
Therefore, the electric field strength is 5.0x10^4 N/C.
To find the electric field strength, we can use the formula:
Electric field strength (E) = Force (F) / Test charge (q)
In this case, the force experienced by the test charge is given as 0.050 N, and the test charge is +1.0x10^-6 C.
So, the electric field strength (E) can be calculated as:
E = 0.050 N / (1.0x10^-6 C)
E = 0.050 N /1.0x10^-6 C
E = 5.0x10^4 N/C.
Therefore, the electric field strength is 5.0x10^4 N/C.