A metal x with relative atomic mass 56 forms an oxide with formula x2O3 . How many grams of metal will combine with 10g of oxygen?(o= 16)
?X + ?O2 --- > ? X2O3 well we will need at least 6 O atoms
4 X + 3 O2 ---> 2 X2 O3
so 10 g O
mols O * 16 grams/ mol = 10 grams
that is 10/16 = 0.625 mols O
every mol of X2O3 contains 3 mols of O
so we have 0.625/3 = 0.298 mols of X2O3 or 0.596 mols of X
.596 * 56 = ?
Good
Good, but I don't really understand
thanks
I need some explanation to decode this please
I am explanation to decode this pls
To calculate the concentration of Cl ions in a 0.3 M sodium chloride (NaCl) solution, we need to use the formula:
concentration (in g/dm3) = molarity (in mol/dm3) x formula weight (in g/mol)
The formula weight of NaCl is 58.44 g/mol, which means each mole of NaCl contains 1 mole of Cl ions. Therefore, the 0.3 M NaCl solution contains 0.3 moles of Cl ions per liter.
Now we can calculate the concentration of Cl ions in g/dm3:
concentration (in g/dm3) = 0.3 mol/dm3 x 35.45 g/mol
concentration = 10.635 g/dm3
Therefore, the concentration of Cl ions in a 0.3 M NaCl solution is 10.635 g/dm3.