THREE BAG OF WHEAT CONTAIN 120 kg, 125 kg and 100 kg wheat respectively. if each bag is to empty in smaller sacks of equal weights. how much wheat is to be field in smaller sacks

field? what does that mean? sheesh!

100 = 2^2 * 5^2
120 = 2^3 * 3 * 5
125 = 5^3
GCF(100,120,125) = 5
so divide each weight by 5

Good

To find out how much wheat is to be filled in smaller sacks, we need to determine the weight of each smaller sack.

Let's assume the weight of each smaller sack is 'x' kg.

Since we have three bags of wheat weighing 120 kg, 125 kg, and 100 kg respectively, we can calculate the total weight of all the wheat as follows:

Total weight of wheat = 120 kg + 125 kg + 100 kg = 345 kg

Now, let's assume that the number of smaller sacks required from each bag is 'a', 'b', and 'c' respectively.

So, we can write the following equations:
120 kg = ax kg
125 kg = bx kg
100 kg = cx kg

To find the value of 'x', we can divide each equation by their respective weights:
120 kg / a = x
125 kg / b = x
100 kg / c = x

Since the weight of each smaller sack is equal, we can equate these values of 'x' and solve for 'x'.

120 kg / a = 125 kg / b = 100 kg / c

From here, we can solve these ratios and find out the values of 'a', 'b', and 'c'. Once we know the values of 'a', 'b', and 'c', we can substitute them back into any of the equations to find the weight of each smaller sack.

My doubt is not clear.

My doubt is not clear .and i was asking other question and you are giving answer of other question