These statements describe a solution region for a system of linear inequalities:
The intersections of its three boundaries are at (0, 4), (6, 1), and (0, 2).
The boundary that is farthest left is dashed and vertical, and it intercepts the xaxis at (0,
0).
The boundary at the top is solid, with a yintercept of 4 and a slope of 1/2.
The boundary at the bottom is solid, with a slope of 1/2 and an xintercept of 4.
The solution region is found in two quadrants.
Use these statements to identify the system of linear inequalities, and then graph the system.
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1 answer

top
y = .5 x + 4
bottom
y = .5 x + b and goes through (4, 0)
0 = 2 + b so b = 2
y = .5 x  2
left is x = 0 vertical (the y axis)
so a triangle shaded inside in quadrants 1 and 4
x > 0
y </= 0.5 x +4
y >/= +0.5 x  2 👍
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answered by Anonymous
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