Use benchmarks to estimate the sum.
three-fifths+start fraction 3 over 17 end fraction
A. 2
B. one-half
C. 1
D. 0
Estimate the difference.
6five twelvths – 4one ninth
A. 2
B. 3
C. 1
D. 4
Estimate the product.
6four elevenths×2one over twelve
A. 18
B. 14
C. 12
D. 13
Find the sum.
start fraction 1 over 6 end fraction+start fraction 1 over 6 end fraction
A. 2
B. one-eighteenth
C. start fraction 1 over 6 end fraction
D. one-third
–start fraction 5 over 6 end fraction+ Start Fraction 6 over 18 End Fraction
A. –one-half
B. start fraction 12 over 49 end fraction
C. –1start fraction 1 over 6 end fraction
D. 12
7start fraction 3 over 10 end fraction + 6start fraction 1 over 5 end fraction
A. 13start fraction 4 over 15 end fraction
B. 13one-half
C. 13Start Fraction 2 over 25 End Fraction
D. 13 start fraction 1 over 5 end fraction
start fraction 7 over 12 end fraction –one-half
A. 3Start fraction 5 over 12 End fraction
B. start fraction 1 over 12 end fraction
C. three-fifths
D. one-fourth
–3start fraction 3 over 7 end fraction– 1start fraction 2 over 7 end fraction
A. 2start fraction 1 over 14 end fraction
B. –4start fraction 1 over 7 end fraction
C. –4start fraction 5 over 7 end fraction
D.
2start fraction 1 over 7 end fraction
8three-fourths– 2start fraction 5 over 8 end fraction
A. 6one-eighth
B. 6one-half
C. 5start fraction 5 over 6 end fraction
D. 5start fraction 15 over 16 end fraction
Find the product.
six sevenths of 21
A. 3
B. 18
C. 126
D. 21six sevenths
five sixths× 24
A. 120
B. 24five sixths
C. 20
D. 4
Start Fraction 1 over 11 End Fraction × three-ninths
A. start fraction 1 over 33 end fraction
B. start fraction 14 over 33 end fraction
C. start fraction 1 over 5 end fraction
D. start fraction 4 over 99 end fraction
3start fraction 2 over 5 end fraction× 5one-half
A. 8start fraction 1 over 5 end fraction
B. 15start fraction 1 over 5 end fraction
C. 18start fraction 7 over 10 end fraction
D. 15start fraction 3 over 10 end fraction
Find the quotient.
start fraction 3 over 13 end fraction÷ one-third
A. 1start fraction 4 over 9 end fraction
B. start fraction 22 over 39 end fraction
C. Start Fraction 9 over 13 End Fraction
D. Start Fraction 1 over 13 End Fraction
start fraction 2 over 3 end fraction÷Start Fraction 8 over 9 End Fraction
A. 1start fraction 1 over 3 end fraction
B. three-fourths
C. 1start fraction 5 over 9 end fraction
D. start fraction 16 over 27 end fraction
–9 ÷ five eighths
A. –eight over forty five
B. 5 over 72
C. –14two fifths
D. 5five eighths
Chase is making calzones that require 2three-fourthspounds of beef. He only has 1start fraction 1 over 6 end fractionpound left. How much more does he need?
A. 1start fraction 7 over 12 end fraction pound
B. 1start fraction 1 over 6 end fraction pound
C. start fraction 5 over 6 end fraction pound
D. start fraction 11 over 12 end fractionpound
see related questions below
and stop with the start fraction ... end fraction nonsense.
Just type your fractions, as in 7/12
To estimate the sum of three-fifths and start fraction 3 over 17 end fraction, you can use benchmark fractions. The benchmark fraction for three-fifths is one-half (which is 0.5), and the benchmark fraction for start fraction 3 over 17 end fraction is start fraction 1 over 6 end fraction (which is approximately 0.17).
So, the estimated sum would be approximately 0.5 + 0.17 = 0.67.
Therefore, the answer is A. 2.
To estimate the sum, sum, difference, product, or quotient, we can use benchmarks. Benchmarks are numbers that are easy to work with mentally, such as 0, 1, 10, 100, etc. We can use benchmarks to round the given numbers and perform approximations to get an estimate of the answer.
Let's go through each question and use benchmarks to estimate the answers:
1. Estimate the sum: three-fifths + (3/17)
Since we need to estimate the sum, we can round the fractions to the nearest benchmark. In this case, we can simplify three-fifths to approximately one-half (since 3/5 is close to 1/2) and (3/17) to approximately zero (since 3/17 is close to zero).
So, the estimated sum would be approximately one-half + zero = one-half (Answer B).
2. Estimate the difference: 6(5/12) - 4(1/9)
Similar to the previous question, we can round the fractions to the nearest benchmark. Here, 6(5/12) is close to 6(1/2) = 3, and 4(1/9) is close to zero.
Therefore, the estimated difference would be approximately 3 - zero = 3 (Answer B).
3. Estimate the product: 6(4/11) × 2(1/12)
Again, we can round the fractions. 6(4/11) is close to 6(1/2) = 3, and 2(1/12) is close to zero.
Thus, the estimated product would be approximately 3 × zero = zero (Answer D).
4. Find the sum: (1/6) + (1/6)
Here, we don't need to estimate since the numbers involved are already simple fractions. Adding (1/6) + (1/6) gives us 2/6, which simplifies to 1/3 (Answer D).
5. (-5/6) + (6/18)
Similarly, we don't need to estimate here. Adding (-5/6) + (6/18) gives us (-25/18), which simplifies to (-1(1/6)). So, the answer is (C) -1(1/6).
6. 7(3/10) + 6(1/5)
We can estimate here by rounding the fractions. 7(3/10) is close to 7(1/3) = 2(1/3), and 6(1/5) is close to 6(1/5) = 1(1/5).
Therefore, the estimated sum is approximately 2(1/3) + 1(1/5) = 13(4/15) (Answer A).
7. (7/12) - (1/2)
No need to estimate since the fractions are simple. Subtracting (7/12) - (1/2) gives us 3(5/12) (Answer A).
8. -3(3/7) - 1(2/7)
Again, no need to estimate. Subtracting -3(3/7) - 1(2/7) gives us -4(5/7) (Answer C).
9. 8(3/4) - 2(5/8)
No estimation needed. Subtracting 8(3/4) - 2(5/8) gives us 6(1/2) (Answer B).
10. Find the product: (6/7) × 21
No estimation needed. Multiplying (6/7) × 21 gives us 18 (Answer A).
11. (5/6) × 24
No estimation needed. Multiplying (5/6) × 24 gives us 20 (Answer C).
12. (1/11) × (3/9)
No estimation needed. Multiplying (1/11) × (3/9) gives us 1/33 (Answer A).
13. 3(2/5) × 5(1/2)
No estimation needed. Multiplying 3(2/5) × 5(1/2) gives us 15(3/10) (Answer D).
14. (3/13) ÷ (1/3)
No estimation needed. Dividing (3/13) ÷ (1/3) gives us 9/13 (Answer C).
15. (2/3) ÷ (8/9)
No estimation needed. Dividing (2/3) ÷ (8/9) gives us 8/9 (Answer C).
16. -9 ÷ (5/8)
No estimation needed. Dividing -9 ÷ (5/8) gives us -14(2/5) (Answer C).
17. Chase needs to know how much more beef he needs. He requires 2(3/4) pounds and has only 1(1/6) pounds left. To find how much more he needs, we can subtract the amount he already has from the total amount required.
Thus, the difference would be 2(3/4) - 1(1/6) = 1(7/12) pounds (Answer A).
Please note that these are estimated answers derived using benchmarks. The exact answers may differ slightly.