A boy drops a coin from the top of a tower 50 metres high find the time taken by the coin to reach the ground
very since
To find the time it takes for the coin to reach the ground, we can use the equation for free fall motion. The equation is given by:
h = (1/2) * g * t^2
where:
h is the height of the tower (50 meters)
g is the acceleration due to gravity (9.8 m/s^2)
t is the time taken for the coin to reach the ground (unknown)
To solve for t, we rearrange the equation:
t^2 = (2 * h) / g
t^2 = (2 * 50) / 9.8
t^2 = 102 / 9.8
t^2 ≈ 10.408
Taking the square root of both sides:
t ≈ √10.408
t ≈ 3.22
Therefore, the time taken by the coin to reach the ground is approximately 3.22 seconds.
To find the time taken by the coin to reach the ground, we can use the formula for the time of free fall. The equation is given by:
t = √(2h/g)
Where:
t = time taken (in seconds)
h = height of the tower (in meters)
g = acceleration due to gravity (approximately 9.8 m/s²)
In this case, the height of the tower is 50 meters. Plugging in the values into the formula:
t = √(2 * 50 / 9.8)
Now, let's solve the equation step by step:
t = √(100 / 9.8)
t = √10.204
t ≈ 3.19 seconds
Therefore, it would take approximately 3.19 seconds for the coin to reach the ground.
ignoring air resistance,
1/2 gt^2 = 50
You know g, so find t