1. Three resistors are placed in series. They have the following resistances: R1 = 20 ohms, R2 = 20 ohms, R3 = 10 ohms. What current would be moved through this circuit by a 5-V power supply?
A. 1.0 A
B. 0.10 A
C. 25 A
D. 250 A
2. Two resistors are placed in a parallel circuit, with R1 = 5 ohms and R2 = 5 ohms. What is the total current that would be moved through this circuit by a 10-volt power supply?
A. 1.0 A
B. 4.0 A
C. 100 A
D. 25 A
3. A current of 10 A moves through a circuit that contains multiple resistors in parallel. Which statement correctly describes the current through the resistors?
A. The current will be greatest through the resistor with the highest resistance.
B. The current will travel only through the resistor with the least resistance.
C. The current through each resistor will be 10 A.
D. The current through all of the resistors will add up to 10 A.
4. A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is also 10 V. What is the voltage provided by the power supply in this circuit?
A. –20 V
B. 10 V
C. 20 V
D. –10 V
5. A 10-volt battery is connected to a circuit with two resistors, R1 and R2, in parallel. If R1 is greater than R2, what does Kirchhoff's loop rule indicate about the voltage drops across the resistors?
A. The voltage drops across both R1 and R2 will be 10 V each.
B. The voltage drops across both R1 and R2 will be 5 V each.
C. The voltage drop across R1 will be greater than the voltage drop across R2.
D. The voltage drop across R1 will be less than the voltage drop across R2.
My Answers:
1. C
2. D
3. A
4. A
5. B
1) 0.10 A
2) 4.0 A
3) The current through all of the resistors will *add up to* 10 A.
4) 20 V
5) The voltage drops across both R1 and R2 will be 10 V each.
y'know oobleck this site is called "Jiskha Homework Help" not "Jiskha Homework Ridicule" just telling someone that they're wrong isn't gonna help :|
Honors student is 100% correct.thank you
haha so true gaia
Q1. (B)
Q2. (B)
Q3. (D)
Q4. (C)
Q5. (A)
1. To find the current through a series circuit, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the total resistance (R).
In this case, the total resistance (R_total) is the sum of all the resistances in the circuit. So R_total = R1 + R2 + R3 = 20 + 20 + 10 = 50 ohms.
Now we can plug in the values into the formula I = V/R. The voltage (V) is given as 5 volts. Hence, I = 5/50 = 0.1 A.
Therefore, the correct answer is B. 0.10 A.
2. When resistors are connected in parallel, the total resistance (R_total) can be calculated using the formula 1/R_total = 1/R1 + 1/R2.
In this case, R_total = 1/5 + 1/5 = 2/5 = 0.4 ohms.
To find the total current (I), we can again use Ohm's Law: I = V/R. V is given as 10 volts, and R is the total resistance, which is 0.4 ohms. Therefore, I = 10/0.4 = 25 A.
Hence, the correct answer is D. 25 A.
3. When resistors are connected in parallel, the current splits at the junction and flows through each resistor. The total current flowing into the junction is equal to the sum of the currents flowing through each resistor.
In this case, the total current is given as 10 A. Therefore, the current through each resistor will be 10 A.
Hence, the correct answer is C. The current through each resistor will be 10 A.
4. The voltage supplied by the power supply in a circuit is equal to the sum of the individual voltage drops across all the components in the circuit.
In this case, the voltage drop across each resistor is given as 10 V. Since the resistors are in series, the total voltage provided by the power supply will be the sum of these voltage drops, which is 10 + 10 = 20 V.
Hence, the correct answer is C. 20 V.
5. According to Kirchhoff's loop rule, the sum of the voltage drops across all the components in a closed loop must be equal to the applied voltage.
In this case, the applied voltage is 10 V. Since resistors R1 and R2 are in parallel, they have the same voltage drop across them. Therefore, the voltage drop across both R1 and R2 will be 10 V each.
Hence, the correct answer is A. The voltage drops across both R1 and R2 will be 10 V each.
#1. No. E = IR and R=20+20+10
#2. No. E = IR and 1/R = 1/5 + 1/5
#3. No. Try D
#4. Nope.
#5. Nope.
Still guessing?