An object is acted upon by two forces of 5N and 12N .calculate the resultant of the two vector if the force act perpendicular to each other
To calculate the resultant of the two forces, we need to use the Pythagorean theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the two forces are acting perpendicular to each other, which means they form a right-angled triangle. Let's consider the force of 5N as one side, and the force of 12N as the other side.
Using the Pythagorean theorem, we can calculate the resultant force as follows:
Resultant force^2 = 5N^2 + 12N^2
= 25N^2 + 144N^2
= 169N^2
Taking the square root of both sides, we get:
Resultant force = √169N^2
= √169 * √N^2
= 13N
Therefore, the resultant of the two forces of 5N and 12N, acting perpendicularly to each other, is 13N.
To find the resultant of two perpendicular forces, you can use the Pythagorean theorem. The Pythagorean theorem states that the square of the hypotenuse (the longest side) of a right triangle is equal to the sum of the squares of the other two sides.
In this case, the two forces (5N and 12N) form the sides of a right triangle. Let's call the resultant force "R". According to the Pythagorean theorem:
R^2 = (5N)^2 + (12N)^2
R^2 = 25N^2 + 144N^2
R^2 = 169N^2
Taking the square root of both sides gives us:
R = √169N^2
R = 13N
Therefore, the resultant of the two vectors, when they are perpendicular to each other, is 13N.