Why do the graphs of reciprocals of linear functions always have vertical asymptotes, but the graphs of reciprocals of quadratic functions sometimes do not? Justify with an example.

except for horizontal lines, there is a point where y=0

The reciprocal would have you divide by zero, which is undefined.

Some quadratic functions, such as y = x^2+1 are never zero, so 1/y is always defined.

Well, imagine you're at a party and there's a super tall person who just loves giving hugs. Let's call him "Mr. Linear." Now, as you approach Mr. Linear for a hug, there's a certain distance that you can get close to him but never quite reach him. This distance is like a "vertical asymptote" because no matter how hard you try, you can't actually touch him.

Now, let's move on to the lovely "Ms. Quadratic." She's a bit different from Mr. Linear because she's not as tall. As you go in for a hug, you can actually reach her and give her a big ol' squeeze. There's no vertical asymptote because, well, you can actually get there!

So, in math terms, the reciprocal of a linear function always has a vertical asymptote because it can never quite equal zero, no matter how large or small the x-values are. But for a quadratic function, if it has a vertex above or below the x-axis, then it won't have a vertical asymptote because there's always a value that can get you close to zero.

As an example, let's look at the linear function f(x) = 3x + 2. Its reciprocal is g(x) = 1/(3x + 2). No matter how large or small x gets, g(x) can never equal zero. So, it has a vertical asymptote at x = -2/3.

Now, let's take the quadratic function f(x) = x^2 - 4. Its reciprocal is g(x) = 1/(x^2 - 4). If we plug in x = 2 or x = -2, g(x) will be zero. So, there are no vertical asymptotes because the function can actually hit zero.

I hope that clears things up while brightening your day with a touch of clownish humor!

The graphs of reciprocals of linear functions always have vertical asymptotes because linear functions have a constant rate of change. This means that as the input values get larger or smaller, the output values get closer and closer to zero, but they never actually reach zero. Therefore, the reciprocals of linear functions approach zero as the input values approach positive or negative infinity, resulting in vertical asymptotes.

On the other hand, the graphs of reciprocals of quadratic functions sometimes do not have vertical asymptotes. This is because quadratic functions can have a maximum or minimum value, known as the vertex, which can be above or below the x-axis. In such cases, the values of the quadratic function do not approach infinity or negative infinity, resulting in the absence of vertical asymptotes for their reciprocals.

For example, let's consider the quadratic function f(x) = x^2 - 1. The graph of this function is a parabola that opens upwards and has a vertex at (0, -1). The values of f(x) approach negative infinity as x approaches negative infinity, and they approach positive infinity as x approaches positive infinity. Therefore, the vertical asymptote for the reciprocal function 1/f(x) will occur at x = 0, since f(x) does not approach infinity or negative infinity at that point.

To understand why the graphs of reciprocals of linear functions always have vertical asymptotes, but the graphs of reciprocals of quadratic functions sometimes do not, we need to examine their characteristics and behaviors.

Let's start with the graph of a linear function in the form of f(x) = mx + b, where m and b are constants. The reciprocal of this linear function is given by g(x) = 1/(mx + b).

For vertical asymptotes to exist, we need to find the values of x for which g(x) approaches positive or negative infinity. Since division by zero is undefined, the denominator mx + b must equal zero to cause such a behavior. Thus, the vertical asymptote occurs at x = -b/m. This means that the graph of the reciprocal of a linear function always has a vertical asymptote.

Now, let's consider the graph of a quadratic function in the form of f(x) = ax² + bx + c, where a, b, and c are constants. The reciprocal of this quadratic function is given by g(x) = 1/(ax² + bx + c).

To determine if a quadratic reciprocal has vertical asymptotes, we need to check if there are any x-values that make g(x) approach infinity or negative infinity. This occurs when the quadratic denominator, ax² + bx + c, becomes very close to zero. However, quadratic functions can have x-intercepts instead of vertical asymptotes if the quadratic equation ax² + bx + c = 0 has real solutions.

For example, let's consider the quadratic function f(x) = x² - 1. Its reciprocal is g(x) = 1/(x² - 1). To find out if this reciprocal has a vertical asymptote, we set the denominator equal to zero: x² - 1 = 0. Solving this equation, we find that x = -1 and x = 1. These are the x-intercepts of the quadratic function f(x), which means that the reciprocal function g(x) does not have vertical asymptotes.

In summary, the graphs of reciprocals of linear functions always have vertical asymptotes because the denominator, which is a linear expression, can equal zero at one and only one x-value. On the other hand, the graphs of reciprocals of quadratic functions sometimes do not have vertical asymptotes because the quadratic denominator can equal zero at more than one x-value, resulting in x-intercepts instead.