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A 12 foot ladder is leaning against a wall. If the top slips down the wall at a rate of 4 ft/s, how fast will the foot be moving away from the wall when the top is 7 feet above the ground?

1 answer

  1. w^2 + g^2 = 12^2
    ... 7^2 + g^2 = 12^2
    ... g = √95

    2 w dw/dt + 2 g dg/dt = 0

    (2 * 7 * -4) + (2 * √95 * dg/dt) = 0

    solve for dg/dt

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