The 6th term of a GP is 2/27 and it's first term is 18, what is the common ratio
ar^5/ar = (2/27)/18
r^5 = 1/243
r = 1/3
you are wrong, but let me solve it am coming
you are right.
thank you.
am soorry.
approve your answer
To find the common ratio (r) of a geometric progression, we can use the formula:
An = A1 * r^(n-1)
where An is the nth term of the geometric progression, A1 is the first term, and n is the term number.
In this case, we are given that the 6th term (A6) is 2/27 and the first term (A1) is 18. Using the formula, we can substitute these values to find the common ratio (r).
2/27 = 18 * r^(6-1)
Simplifying the equation, we get:
2/27 = 18 * r^5
Next, we can divide both sides of the equation by 18:
(2/27) / 18 = r^5
2/486 = r^5
To solve for r, we can take the fifth root of both sides of the equation:
r = (2/486)^(1/5)
Calculating this expression, we find that r is approximately 1/3.
Therefore, the common ratio of the geometric progression is 1/3.