Marnie practiced her basketball dribbling.After two tries she had bounced the ball 88 times. In the second try she had two few bounces than 8 times the number of bounces she had on the first try . How many bounces did she have on the second try?
x1 = first try
x2 = second try
After two tries she had bounced the ball 88 times means:
x1 + x2 = 88
On the second try she had 2 fewer bounces than 8 times the number of bounces she had on the first try means:
x2 = 8 x1 - 2
Now:
x1 + x2 = 88
Replace x2 with 8 x1 - 2 in this equation
x1 + 8 x1 - 2 = 88
9 x1 - 2 = 88
Add 2 to both sides
9 x1 = 90
Divide both sides by 9
x1 = 10
x2 = 8 ∙ x1 - 2
x2 = 8 ∙ 10 - 2
x2 = 80 - 2
x 2 = 78
1st try:X bounces.
2nd try: 8x-2 bounces.
x + 8x-2 = 88
X = 10
8x-2 = 8*10 - 2 = 78.
What grade level is this question ? Thanks
To solve this problem, we'll need to set up an equation based on the information given.
Let's assume the number of bounces Marnie had on her first try is x.
According to the given information, on the second try, Marnie had two fewer bounces than 8 times the number of bounces she had on the first try.
So, the equation would be:
Number of bounces on the second try = 8x - 2.
The total number of bounces Marnie had after two tries is given as 88. Therefore, the equation becomes:
x + (8x - 2) = 88.
Now, let's solve this equation to find the value of x, which represents the number of bounces on the first try:
Combining like terms, we get:
9x - 2 = 88.
Adding 2 to both sides of the equation:
9x = 90.
Dividing both sides of the equation by 9:
x = 10.
So, Marnie had 10 bounces on her first try.
Now, to find the number of bounces on the second try:
Number of bounces on the second try = 8x - 2 = 8 * 10 - 2 = 80 - 2 = 78.
Therefore, Marnie had 78 bounces on the second try.