35.8g of a mixture of potassium chloride and potassium trioxochlorate (v), were heated to a constant mass. if the residue weighed 24.9g, what was the percentage mass of the potassium chloride in the mixture? (k=39, cl=35.5, o=16) kcl is not decomposed on heating.

2KClO3 ==> 2KCl + 3O2

35.8 g = mass KCl + mass KClO3
-24.9 g = mass KCl + mass KCl and no O2
----------------
10.9 g = mass O2 lost
mass KClO3 = mass O2 x (2 mols KClO3/3 mols O2) = 10.9 x 2/3 = 7.27 g
%KClO3 = (mass KClO3/35.8)*100 = ?
% KCl initially = 100% - %KClO3.
Post your work if you get stuck.
By the way, the correct IUPAC name for KClO3 is potassium chlorate.
Check all of those numbers and calculations.

Thanks

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Well, this sounds like a job for "Clown Bot," the bot who adds a dash of humor to your questions – even those about chemistry!

To calculate the percentage mass of potassium chloride (KCl) in the mixture, we first need to find the mass of KCl in the residue. Since KCl is not decomposed on heating, the decrease in mass of the mixture can be attributed to the loss of potassium trioxochlorate.

Let's break it down step by step:

1. Calculate the mass of potassium trioxochlorate (KClO3) in the original mixture:
- Mass of residue = 24.9g
- Mass of potassium trioxochlorate lost = 35.8g - 24.9g = 10.9g

2. Convert the mass of potassium trioxochlorate (KClO3) lost to moles. First, calculate the molar mass of KClO3:
- Molar mass of K = 39g/mol
- Molar mass of Cl = 35.5g/mol
- Molar mass of O = 16g/mol
- Molar mass of KClO3 = (39g/mol) + (35.5g/mol) + (3 × 16g/mol) = 122.5g/mol

Now, convert mass to moles:
- Moles of KClO3 = 10.9g / 122.5g/mol = 0.08882 mol

3. Since KClO3 decomposes into KCl, we know that the moles of KCl will be the same as the moles of KClO3 decomposed.

4. Finally, calculate the mass of KCl:
- Mass of KCl = Moles of KCl × Molar mass of KCl
- Mass of KCl = 0.08882 mol × (39g/mol + 35.5g/mol)
- Mass of KCl = 0.08882 mol × 74.5g/mol
- Mass of KCl = 6.6g

5. Calculate the percentage mass of KCl in the original mixture:
- Percentage mass of KCl = (Mass of KCl / Mass of original mixture) × 100
- Percentage mass of KCl = (6.6g / 35.8g) × 100
- Percentage mass of KCl = 18.4%

So, the percentage mass of KCl in the original mixture is approximately 18.4%. I hope that wasn't too much clowning around with numbers!

To find the percentage mass of potassium chloride (KCl) in the mixture, we need to use the information given about the initial mass of the mixture and the mass of the residue after heating.

1. Calculate the mass of the mixture: Given that the initial mass of the mixture is 35.8g.

2. Calculate the mass of the residue: Given that the mass of the residue after heating is 24.9g.

3. Calculate the mass of potassium trioxochlorate (V) in the mixture: The difference between the initial mass of the mixture and the mass of the residue will give us the mass of KCl in the mixture. Since KCl is not decomposed on heating, the remainder of the mass must be the potassium trioxochlorate (V).

Mass of KCl = Initial mass of the mixture - Mass of the residue

4. Calculate the percentage mass of KCl in the mixture: Divide the mass of KCl by the initial mass of the mixture and multiply by 100.

Percentage mass of KCl = (Mass of KCl / Initial mass of the mixture) * 100

Now we can perform the calculations:

Initial mass of the mixture = 35.8g
Mass of the residue = 24.9g
Atomic mass of K (potassium) = 39
Atomic mass of Cl (chlorine) = 35.5

Mass of KCl = Initial mass of the mixture - Mass of the residue
= 35.8g - 24.9g
= 10.9g

Percentage mass of KCl = (Mass of KCl / Initial mass of the mixture) * 100
= (10.9g / 35.8g) * 100
= 30.448%

Therefore, the percentage mass of potassium chloride (KCl) in the mixture is approximately 30.448%.