1. The electrostatic force between two charges is originally F. Which expression represents the new electrostatic force between the two charges if one charge doubles and the other one is divided by three?
A. 3/2 F
B. 2/3 F
C. 1/6 F
D. 6 F
2. Suppose the electrostatic force between two electrons is F. What is the electrostatic force between an electron and a proton that are the same distance apart?
A. 2 F
B. -F/2
C. F/2
D. -F
3. Two charges q1 and q2 are both negative. Which statement describes the electrostatic force between the two charges?
A. The force is represented as a negative quantity and is attractive.
B. The force is represented as a positive quantity and is repulsive.
C. The force is represented as a positive quantity and is attractive.
D. The force is represented as a negative quantity and is repulsive.
4. Which statement describes the relationship between the distance between two charges and the electrostatic force between them?
A. Electrostatic force is inversely proportional to the square of the distance.
B. Electrostatic force is inversely proportional to the distance.
C. Electrostatic force is directly proportional to the distance.
D. Electrostatic force is directly proportional to the square of the distance.
5. What happens to the electrostatic force between two opposite charges of equal magnitude if the negative charge is replaced with a positive charge and the distance between them is halved?
A. The direction of the force stays the same, and the magnitude of the force quadruples.
B. The direction of the force stays the same, and the magnitude of the force doubles.
C. The direction of the force changes, and the magnitude of the force quadruples.
D. The direction of the force changes, and the magnitude of the force doubles.
My answers:
1. A
2. D
3. C
4. B
5. D
2/3
-F
The force is represented as a positive quantity and is repulsive
Electrostatic force is inversely proportional to the square of the distance
The direction of the force changes and the magnitude of the force quadruples
Nada is right I got 100%!
Thanks nada. 100%
is this for connections?
its still rightn now btw
Yes.
still right
1. To find the new electrostatic force between the two charges, we need to consider how the charges have changed. Let's call the original charges q1 and q2, and their initial electrostatic force F.
If one charge doubles, its new value is 2q2. If the other charge is divided by three, its new value is q1/3.
The expression for the new electrostatic force is given by Coulomb's law: F' = k * (q1/3) * (2q2) / r^2, where k is the electrostatic constant and r is the distance between the charges.
Simplifying this expression, we get F' = 2/3 * F.
So, the correct answer is A. 3/2 F.
2. The electrostatic force between two charges is given by Coulomb's law: F = k * (q1 * q2) / r^2, where k is the electrostatic constant, q1 and q2 are the charges, and r is the distance between them.
In this case, the electrostatic force between two electrons is F.
If we consider an electron and a proton with the same distance between them, they have opposite charges (electron is negative, proton is positive).
The expression for the electrostatic force between them is then F' = k * (e * p) / r^2, where e and p are the charges of an electron and proton, respectively.
Since the electron and proton have the same magnitude of charge, we can replace e and p with the same value q.
Therefore, F' = k * (q * q) / r^2 = k * (q^2) / r^2.
So, the correct answer is A. 2 F.
3. When two charges of the same sign are placed near each other, the electrostatic force between them is repulsive. In this case, both charges q1 and q2 are negative.
The statement that describes the electrostatic force between the two charges is:
D. The force is represented as a negative quantity and is repulsive.
4. According to Coulomb's law, the electrostatic force between two charges is inversely proportional to the square of the distance between them.
This means that as the distance between the charges increases, the electrostatic force decreases, and vice versa.
The correct answer is A. Electrostatic force is inversely proportional to the square of the distance.
5. To determine the effect of replacing the negative charge with a positive charge and halving the distance between the charges, we need to consider Coulomb's law and the behavior of opposite charges.
Originally, the electrostatic force between two opposite charges of equal magnitude is attractive, pulling the charges towards each other.
If we replace the negative charge with a positive charge, the charges are now both positive. According to Coulomb's law, like charges repel each other.
Additionally, halving the distance between the charges increases the strength of the electrostatic force.
So, the correct answer is D. The direction of the force changes, and the magnitude of the force doubles.