PLEASE PLEASE HELP ?!
To rent a certain meeting room, a college charges a reservation fee of $45 and an additional fee of $7.40 per hour. The chemistry club wants to spend less than
$111.60 on renting the meeting room.
What are the possible amounts of time for which they could rent the meeting room?
Use for the number of hours the meeting room is rented, and solve your inequality for t.
45 + 7.40t < 111.60
i have this question too!!
To find the possible amounts of time for which the chemistry club could rent the meeting room, we need to solve the inequality:
45 + 7.40t < 111.60
First, let's subtract 45 from both sides of the inequality:
7.40t < 111.60 - 45
7.40t < 66.60
Next, let's divide both sides of the inequality by 7.40 to solve for t:
t < 66.60 / 7.40
t < 9
Therefore, the chemistry club could rent the meeting room for any amount of time less than 9 hours.
To find the possible amounts of time for which the chemistry club could rent the meeting room, we will set up an inequality based on the given information.
Let's start by identifying the variables in the problem:
Reservation fee = $45
Additional fee per hour = $7.40
Maximum rental cost = $111.60
Number of hours rented = t (unknown)
Based on the information given, we can set up the inequality:
Reservation fee + (Additional fee per hour) * (Number of hours rented) ≤ Maximum rental cost
Substituting the given values:
$45 + $7.40t ≤ $111.60
To solve this inequality for t, we will follow these steps:
Step 1: Subtract $45 from both sides of the inequality:
$7.40t ≤ $111.60 - $45
Simplifying:
$7.40t ≤ $66.60
Step 2: Divide both sides of the inequality by $7.40 to isolate t:
t ≤ $66.60 / $7.40
Simplifying:
t ≤ 9
The solution to the inequality is t ≤ 9. This means the chemistry club can rent the meeting room for any amount of time up to 9 hours in order to spend less than $111.60.