At the movie theatre, child admission is 5.80$ and adult admission is9.00$ . On Tuesday, 135 tickets were sold for a total sales of1055.00$ . How many child tickets were sold that day?
a+c = 135
9.00a + 5.80c = 1055
now just solve for c
To answer this question, we need to set up and solve a system of equations.
Let's denote the number of child tickets sold as "C" and the number of adult tickets sold as "A". We have two pieces of information:
1) The total number of tickets sold: C + A = 135
2) The total sales: 5.80C + 9.00A = 1055.00
To solve this system of equations, we can use the method of substitution or elimination. Let's use the substitution method:
From equation 1, we can express A in terms of C: A = 135 - C
Substitute this expression for A in equation 2:
5.80C + 9.00(135 - C) = 1055.00
Now, we can simplify and solve for C:
5.80C + 1215.00 - 9.00C = 1055.00
Combine like terms:
-3.20C = -160.00
Divide both sides by -3.20:
C = -160.00 / -3.20
C = 50
Therefore, 50 child tickets were sold that day.
Let's solve this step-by-step.
Let's assume the number of child tickets sold as 'C' and the number of adult tickets sold as 'A'.
We are given the following information:
1. The price of a child ticket is $5.80.
2. The price of an adult ticket is $9.00.
3. On Tuesday, a total of 135 tickets were sold.
4. The total sales amount was $1055.00.
Now, we can create two equations based on the given information:
Equation 1: C + A = 135 (Equation for the total number of tickets sold)
Equation 2: 5.80C + 9.00A = 1055.00 (Equation for the total sales amount)
We can solve this system of equations to find the value of 'C' (the number of child tickets sold).
Let's start by solving Equation 1 for 'A':
A = 135 - C
Now, substitute the value of 'A' in Equation 2:
5.80C + 9.00(135 - C) = 1055.00
Now, simplify and solve for 'C':
5.80C + 1215 - 9.00C = 1055.00
-3.20C = -160
C = -160 / -3.20
C = 50
Therefore, 50 child tickets were sold that day.