Imagine you have two beakers. Both beakers are filled with the same amount of water. The water in both beakers is the same temperature as well. You add 50 g of Substance A to the first beaker, and 50 g of Substance B to the second beaker. After stirring both beakers, there is a small pile of Substance A at the bottom of the first beaker. None of Substance B is visible in the second beaker. Which of the following statements is true?
A. Substance A is less soluble in water than Substance B.
B. Substance A is more soluble in water than Substance B.
C. Substance A is not soluble in water.
D. Substance B is not soluble in water.
So you know B has completely dissolved. Some but not all of A has dissolved. So A is less soluble than B in water.
i agree with bob
hehehee joe
To determine which statement is true, we need to understand the concept of solubility. Solubility refers to the ability of a substance to dissolve in a solvent. In this case, the solvent is water.
In the first beaker, after adding 50 g of Substance A and stirring it, we observe a small pile of Substance A at the bottom. This suggests that Substance A did not fully dissolve in the water. In the second beaker, we do not see any visible trace of Substance B, indicating that it dissolved completely.
Based on these observations, we can eliminate options C and D, which state that either Substance A or Substance B is not soluble in water.
To compare the solubility of Substance A and Substance B, we can consider the amount of substance that dissolved. Since there is a small pile of Substance A at the bottom of the first beaker, it did not dissolve completely, suggesting that it is less soluble in water. On the other hand, no visible trace of Substance B is observed in the second beaker, indicating that it dissolved completely. Therefore, Substance A is less soluble in water than Substance B.
The correct statement is:
A. Substance A is less soluble in water than Substance B.