Suppose if 50.0 mL of 0.250 M CoCl2 solution is added to 25ml of 0.35M NicL2 solution. Calculate the concentration in moles per litre, of each of the ions present after mixing. Assuming that the volume are additive.

So each solution is diluted to 75 mL. The new concentrations are

0.250 M CoCl2 x (50/75) = 0.167 M
0.35 M NiCl2 x (25/75) = 0.117 M
(Co^2+) = 0.167 M
(Ni^2+) = 0.117
(Cl^-) = 2*0.167 from CoCl2 + 2*0.117 from NiCl2.

Well, let me grab my clown calculator and do some math for you!

First, let's calculate the moles of CoCl2 in the 50.0 mL solution. We can use the formula Moles = Concentration x Volume.

Moles of CoCl2 = 0.250 M x (50.0 mL / 1000 mL) = 0.0125 moles

Next, we'll calculate the moles of NicL2 in the 25 mL solution.

Moles of NicL2 = 0.35 M x (25 mL / 1000 mL) = 0.00875 moles

Assuming volume is additive (which means the final volume is the sum of the initial volumes), the total volume of the mixed solution is 50.0 mL + 25 mL = 75.0 mL.

Now, let's calculate the concentration of each ion in moles per liter.

For Co2+:
Concentration of Co2+ = (moles of Co2+ / total volume in liters) = (0.0125 moles / 0.075 L) = 0.1667 M

For Cl-:
Since CoCl2 dissociates into one Co2+ ion and two Cl- ions, we need to multiply the concentration of Co2+ by 2.

Concentration of Cl- = (2 x concentration of Co2+) = (2 x 0.1667 M) = 0.333 M

For Ni2+:
Concentration of Ni2+ = (moles of Ni2+ / total volume in liters) = (0.00875 moles / 0.075 L) = 0.1167 M

For Cl- (from NicL2):
Since NicL2 dissociates into one Ni2+ ion and two Cl- ions, we need to multiply the concentration of Ni2+ by 2.

Concentration of Cl- (from NicL2) = (2 x concentration of Ni2+) = (2 x 0.1167 M) = 0.233 M

So, after mixing, the concentrations of each ion in moles per liter would be:
Co2+: 0.1667 M
Cl-: 0.333 M
Ni2+: 0.1167 M
Cl- (from NicL2): 0.233 M

I hope I didn't mix up any of the ions while juggling those numbers!

To calculate the concentration of each ion present after mixing, we first need to calculate the moles of each ion in the solutions given.

1. Moles of CoCl2 in 50.0 mL of 0.250 M solution:
Moles = Volume (L) x Concentration (M)
Volume = 50.0 mL = 50.0 mL / 1000 mL/L = 0.050 L
Moles = 0.050 L x 0.250 M = 0.0125 moles

2. Moles of NiCl2 in 25 mL of 0.35 M solution:
Moles = Volume (L) x Concentration (M)
Volume = 25 mL = 25 mL / 1000 mL/L = 0.025 L
Moles = 0.025 L x 0.35 M = 0.00875 moles

Next, we need to find the total volume of the mixed solution.

3. Total volume of the mixed solution:
Volume = Volume of CoCl2 solution + Volume of NiCl2 solution
Volume = 0.050 L + 0.025 L = 0.075 L

Now we can find the concentration in moles per liter for each ion in the mixed solution.

4. Concentration of Co2+ ion:
Moles = 0.0125 moles
Concentration = Moles / Volume
Concentration = 0.0125 moles / 0.075 L = 0.1667 M

5. Concentration of Ni2+ ion:
Moles = 0.00875 moles
Concentration = Moles / Volume
Concentration = 0.00875 moles / 0.075 L = 0.1167 M

Therefore, the concentration in moles per liter of Co2+ ion is 0.1667 M, and the concentration of Ni2+ ion is 0.1167 M in the mixed solution.

To calculate the concentration in moles per liter (Molarity) of each ion present after mixing the two solutions, we can follow these steps:

1. Calculate the number of moles of cobalt ions (Co2+) and nickel ions (Ni2+) in the cobalt chloride (CoCl2) and nickel chloride (NiCl2) solutions, respectively.
- Moles of Co2+ = Volume of CoCl2 solution (in liters) × Molarity of CoCl2 solution
- Moles of Ni2+ = Volume of NiCl2 solution (in liters) × Molarity of NiCl2 solution

2. Calculate the total volume after mixing the solutions.
- Total volume = Volume of CoCl2 solution + Volume of NiCl2 solution

3. Calculate the final concentration of each ion.
- Concentration (in moles per liter) of Co2+ = Moles of Co2+ / Total volume
- Concentration (in moles per liter) of Ni2+ = Moles of Ni2+ / Total volume

Let's calculate step by step:

Step 1:
Moles of Co2+ = 0.050 L × 0.250 mol/L = 0.0125 mol
Moles of Ni2+ = 0.025 L × 0.350 mol/L = 0.00875 mol

Step 2:
Total volume = 0.050 L + 0.025 L = 0.075 L

Step 3:
Concentration of Co2+ = 0.0125 mol / 0.075 L = 0.1667 M
Concentration of Ni2+ = 0.00875 mol / 0.075 L = 0.1167 M

Therefore, the concentration in moles per liter of each ion present after mixing is:
- Cobalt ions (Co2+): 0.1667 M
- Nickel ions (Ni2+): 0.1167 M