50 students in a class took me an examination in french and mathematics .If 14 of them pass french only , 23 pass in both subjects and 5 of them failed in both subjects.
Draw a venn diagram to represent the information. Find number of students who pass in french. Find number of students who pass mathematics only
If x passed math only, then
x+23+14 = 50-5
x = 8
14+23+5+x=50=x=50-42=8
I, 14+23=37
II, 23+8=31
31/50
Fifty student in a class took an exam in French and Maths. If 4 of them passed French only,23 passed in both French and Maths and 5 of them failed both subjects.
1. Find the number of students who passed in French
In a class of 70 student, 40 belong to the red Cross society,27 belong to the girls guide society and 12 belong to both the red Cross society and the girls guide society. The remaining student do not belong to any of the two societies.
1. illustrate the information on a Venn diagram
Fifty students took an examination in French only , 23 passed in both French and Mathematics and 5 of them failed in both subjects Find. (I)The number of students who passed in French. (I)The probability of selecting a student who passed in Mathematics
Sure, here is a Venn diagram to represent the information:
______________________
/ \
/ \
/ French Only \
/ (14 students) \
/________________________\
\ /
\ /
\ Both /
\ (23 students) /
\______________________/
French
Now, let's find the number of students who pass in French.
We know that 14 students pass in French only, and 23 students pass in both subjects. So, the total number of students who pass in French is 14 + 23 = 37.
Next, let's find the number of students who pass mathematics only.
We know that 23 students pass in both subjects, and 5 students fail in both subjects. So, the number of students who pass in both subjects is 50 - 23 - 5 = 22.
Therefore, the number of students who pass mathematics only is 22 students.
I hope this helps!
To find the number of students who pass in French, we add up the number of students who pass French only and those who pass both subjects.
Given:
- 14 students pass French only.
- 23 students pass both French and mathematics.
Therefore, the number of students who pass in French is 14 + 23 = 37.
To find the number of students who pass Mathematics only, we subtract the number of students who pass both subjects from the total number of students who took the examination (50).
Given:
- 23 students pass both French and mathematics.
- 5 students failed in both subjects.
Therefore, the number of students who pass Mathematics only is 50 - 23 - 5 = 22.
Now, let's draw a Venn diagram to represent the information:
____F____
| |
____________|__________|_____________
| |
|____M___|
In the diagram:
- F represents the set of students who pass French.
- M represents the set of students who pass Mathematics.
From the given information:
- 14 students pass French only, so we write this number in the F section only.
- 23 students pass both French and mathematics, so we write this number in the overlap between F and M.
- 5 students failed in both subjects, so we write this number outside the F and M sections.
Hope this helps!