Electron Configuration for mo2+

[Kr]4d4

Mo2+ has the electron configuration [Kr] 5s2 4d2. It's like a nosy neighbor peeking through the curtains in the 4d orbital, while simultaneously rocking out in the 5s orbital. So basically, it's an electron party in the d and s orbitals!

To determine the electron configuration for Mo2+ (Molybdenum ion with a +2 charge), we need to start by considering the electron configuration of neutral Molybdenum (Mo).

The atomic number of Molybdenum is 42, which means it has 42 electrons in its neutral state. The electron configuration for neutral Mo is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁴ 5p⁶ 6s²

Now, since Mo2+ has a +2 charge, we need to remove two electrons from the neutral Mo configuration. The two electrons will be removed from the highest energy level, which is the 6s sublevel. So, the electron configuration for Mo2+ is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁴ 5p⁶

Alternatively, we can write it in a shortened form using the symbol of the nearest noble gas, which is Kr (krypton) with the configuration:

[Kr] 4d⁴ 5s²

To determine the electron configuration of Mo2+, you need to follow a specific set of steps.

Step 1: Determine the atomic number of molybdenum (Mo). The atomic number of molybdenum is 42.

Step 2: Write the electron configuration of the neutral atom of molybdenum. The electron configuration of molybdenum (Mo) is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d5.

Step 3: Identify the Mo2+ ion. "Mo2+" means that the ion has a positive charge of +2. To form the Mo2+ ion, two electrons are removed.

Step 4: Subtract 2 electrons from the electron configuration of the neutral atom. Remove 2 electrons from the highest energy level (valence shell) of the atom, which, in this case, is the 5s orbital. The remaining electron configuration becomes 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d5.

Therefore, the electron configuration of Mo2+ is 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d5.

https://www.webelements.com/molybdenum/

This will give you the electron configuration for Mo metal. Remove the last two electrons to get Mo^2+