Read the scenario, then answer the questions.
A 2 kg ball is thrown upward with a velocity of 15 m/s.
What is the kinetic energy of the ball as it is being thrown?
____J
What is the potential energy of the ball when it gets to its maximum height just before falling back to the ground?
____J
Both parts are 225J.
: )
Good soup
To find the kinetic energy of the ball as it is being thrown, you can use the formula: KE = 1/2 * mass * velocity^2.
Given:
Mass of the ball (m) = 2 kg
Velocity of the ball (v) = 15 m/s
Now let's substitute these values into the formula:
KE = 1/2 * 2 kg * (15 m/s)^2
KE = 1/2 * 2 kg * 225 m^2/s^2
KE = 225 Joules
Therefore, the kinetic energy of the ball as it is being thrown is 225 Joules.
Now let's move on to the potential energy of the ball at its maximum height.
When the ball reaches its maximum height, its velocity becomes zero. The potential energy is given by the formula: PE = m * g * h, where m is the mass of the object, g is the acceleration due to gravity, and h is the height.
Given:
Mass of the ball (m) = 2 kg
Acceleration due to gravity (g) = 9.8 m/s^2 (approximately)
Height (h) = ?? (Not provided in the scenario)
Without the height value, we can't calculate the specific potential energy. Please provide the height value, and I can help you calculate the potential energy of the ball at its maximum height.
KE = 1/2 mv^2
at the top, v=0, so all the KE has been converted to PE