When selecting courses for university, Mimi must take 2 math courses, 4 arts courses, 3 sciences courses, and 1 elective. There are 7 math courses to choose from, 10 arts courses, 6 sciences courses, and 5 electives. How many different course selections could she make?
this might take a while ill come back when i have the answer
ok thank you! this is supposed to be for data management course unit 3- combinations.
(just incase you need to know)
ok thanks
7C2 * 10C4 * 6C3 * 5C1 = 441,000
Thanks!
To solve this problem, we can use the concept of combinations.
For the math courses, Mimi needs to select 2 courses out of 7. We can calculate the number of combinations using the formula:
nCr = n! / (r!(n-r)!)
In this case, n is the total number of math courses (7) and r is the number of math courses Mimi needs to select (2).
So, the number of combinations for math courses is:
7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7 * 6 * 5!) / (2! * 5!) = (7 * 6) / 2! = 7 * 6 / 2 = 21
Similarly, for the arts courses, Mimi needs to select 4 out of 10. The number of combinations for arts courses can be calculated as:
10C4 = 10! / (4!(10-4)!) = 10! / (4!6!) = (10 * 9 * 8 * 7) / (4 * 3 * 2 * 1) = (10 * 9 * 8 * 7) / 24 = 210
For the sciences courses, Mimi needs to select 3 out of 6. The number of combinations for sciences courses is:
6C3 = 6! / (3!(6-3)!) = 6! / (3!3!) = (6 * 5 * 4) / (3 * 2 * 1) = 20
Finally, for the elective course, Mimi can choose any 1 out of the 5 electives. So, there are 5 options for the elective course.
To find the total number of course selections, we multiply the number of combinations for each type of course selection:
Total = math combinations * arts combinations * sciences combinations * elective options
Total = 21 * 210 * 20 * 5 = 441,000
Therefore, Mimi could make a total of 441,000 different course selections.