In CuSO4+CoCl2=CuCl2+CoSO4
Are both CuCl2 and CoSO4 aqueous?
CuCl2 is also aqueous
Let me point out two things here.
First, solid USUALLY don't react so most reactions of this type react, if they react at all, because they are in aqueous solution and it's the ions that react.
Second, reactions occur because of a reason.
1. A precipitate is formed.
2. A gas is formed.
3. A slightly ionized substance is formed.
4. A redox (oxidation-reduction) rxn is taking place.
In the above equation none of these is present and there is no reaction. What you have going on is a mixing of the ions in solution.
In the chemical equation CuSO4 + CoCl2 = CuCl2 + CoSO4, both CuCl2 and CoSO4 are aqueous.
To determine whether CuCl2 and CoSO4 are aqueous, we need to understand the solubility rules for common ionic compounds. These rules guide us in determining whether a compound is soluble (aqueous) or insoluble (solid) in water.
For copper(II) chloride (CuCl2), according to the solubility rules, all chlorides are generally soluble except those of silver, lead(II), and mercury(I) ions. Since copper(II) chloride does not fall into any of these exceptions, we can conclude that it is indeed soluble in water (aqueous).
For cobalt(II) sulfate (CoSO4), we can apply similar reasoning. According to the solubility rules, sulfates are generally soluble except those of barium, lead(II), and calcium ions. Cobalt(II) sulfate does not fall into any of these exceptions, so it is also soluble in water (aqueous).
Therefore, both CuCl2 and CoSO4 are aqueous in the given chemical equation.