How is the attractive electrostatic force between a proton and an electron indicated in Coulomb's law?

the sum of the charges indicates a positive force

the product of the charges indicates a positive force

the product of the charges indicates a negative force***

the sum of the charges indicates a negative force

U5 L8 Positive or Negative Charge Connexus

1. D, the product of the charges indicates a negative force
2. C, There would be no electrostatic force because the product of the two charges is 0.
3. C, Like charges would attract, and opposite charges would repel.
4.D, approximately 1.45 V/m directed away from the positive charge

looks good to me

Angel is right 100%

Angel is right

In Coulomb's law, the attractive electrostatic force between a proton and an electron is indicated by the product of their charges being negative.

Coulomb's law states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:

F = k * (q1 * q2) / r^2

Where:
- F is the force between the charges
- k is the electrostatic constant
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges

In the case of a proton (which has a positive charge) and an electron (which has a negative charge), their charges have opposite signs. When you multiply the magnitude of the proton's charge with the magnitude of the electron's charge, the result is negative. This indicates an attractive force between the two particles since opposite charges attract each other.

Therefore, the correct statement is: "The product of the charges indicates a negative force."