Between
11
11 P.M. and
8: 45
8:45 A.M., the water level in a swimming pool decreased by
StartFraction 13 Over 16 EndFraction in
13
16
in. Assuming that the water level decreased at a constant rate, how much did the water level drop each hour?
Mrs.Sue, can you please help me find the proper equation? I can't find it.
you need to learn to type fractions.
11:00 pm to 8:45 am = 9 3/4 hours
so the rate of drop is
(13/16 in)/(9 3/4 hr) = 13/16 * 4/39 = 1/12 in/hr
Well, Mrs. Sue might have some equations for you, but I've got something better - a joke!
Why did the water level in the swimming pool get a promotion? Because it wanted to drop at a constant rate and climb up the corporate ladder, of course!
Okay, okay, back to your question. To find out how much the water level dropped each hour, we need to calculate the total decrease in the water level and divide it by the total time.
First, let's start by converting the given time into minutes. From 11 PM to 8:45 AM, we have a total of 9 hours and 45 minutes. But let's not forget that 45 minutes is three-quarters of an hour! So, we have 9 + (3/4) = 9.75 hours in total.
Now, we'll convert the given decrease in the water level into a decimal. 13/16 is approximately 0.8125.
To find how much the water level dropped each hour, we divide the total decrease (0.8125 inches) by the total time (9.75 hours).
So, the water level dropped approximately 0.0836 inches per hour.
Remember, though, this is all assuming a constant rate. Maybe the pool just wanted to take a quick nap and started losing water at a regular pace. Who knows?
To find the rate at which the water level dropped each hour, we need to determine the total time elapsed during the period and the total decrease in the water level.
Given:
Start time: 11 P.M.
End time: 8:45 A.M.
Water level decreased by 13/16 in.
First, let's convert the given time into a common format (24-hour clock):
Start time: 11:00 PM = 23:00
End time: 8:45 AM = 8:45
To find the elapsed time, we subtract the start time from the end time:
8:45 - 23:00 = 8:45 - 23:00 (convert 8:45 to 24-hour format)
= 8:45 - 23:00
= 8:45 - 23:00 + 24:00 (adding 24 hours to the end time)
= 32:45 - 23:00
= 9 hours and 45 minutes
Now we have the total time elapsed: 9 hours and 45 minutes.
Next, we need to convert the decreases in the water level into inches per hour. To do this, we divide the total decrease by the total time elapsed:
Water level decrease per hour = Total decrease / Total time elapsed
= (13/16) in / 9 hours 45 minutes
To convert 9 hours 45 minutes to decimal form, we divide 45 minutes by 60 (since there are 60 minutes in an hour):
9 hours 45 minutes = 9 hours + (45/60) hours
= 9 hours + 0.75 hours
= 9.75 hours
Now we can calculate the decrease in the water level per hour:
Water level decrease per hour = (13/16) in / 9.75 hours
= (13/16) in * (1/9.75) hours
= (13/16) * (1/9.75) in/hour
≈ 0.8438 in/hour
The water level dropped approximately 0.8438 inches per hour.
Sure! Let's break down the problem and find the proper equation.
We know that the water level in the swimming pool decreased by 13/16 inches between 11 P.M. and 8:45 A.M., which is a time span of 9 hours and 45 minutes.
To find the amount of water level drop per hour, we need to calculate the rate at which the water level dropped.
First, we need to convert the time span of 9 hours and 45 minutes to a decimal hour.
To convert 45 minutes to hours, we divide it by 60 since there are 60 minutes in an hour.
45 minutes = 45/60 = 0.75 hours
Now, we add the 9 hours and 0.75 hours to get the total time in decimals.
Total time = 9 + 0.75 = 9.75 hours
Next, we calculate the amount of water level drop per hour by dividing the total decrease in water level (13/16 inches) by the total time (9.75 hours).
Amount of water level drop per hour = (13/16) / 9.75
Therefore, the equation representing the amount of water level drop per hour would be:
Amount of water level drop per hour = (13/16) / 9.75
Now, you can calculate the value of the equation to find the amount the water level dropped each hour.