Use the angle addition postulate to create and solve and equation for each situation.
m∠AOB = 28, m∠BOC = 3x-2, m∠AOD = 6x
m∠AOB = 4x+3, m∠BOC = 7x, m∠AOD = 16x-1
I don't know what to do. so don't got an answer to share
so m∠AOB = 28, m∠BOC = 3x-2, m∠AOD = 6x. x = 18
add up the measures of adjacent angles to get the measure of the sum
You do not provide any information on how these angles are related.
yes, but which angles are inside which others? I can think of several ways to solve for x, but they depend on where ABCD are located.
To solve these equations using the angle addition postulate, you need to understand that the sum of the angles around a point is 360 degrees.
For the first situation:
m∠AOB = 28
m∠BOC = 3x - 2
m∠AOD = 6x
According to the angle addition postulate, the sum of these three angles is equal to 360 degrees:
m∠AOB + m∠BOC + m∠AOD = 360
Now substitute the given values into the equation:
28 + (3x - 2) + 6x = 360
Combine like terms:
28 + 3x - 2 + 6x = 360
9x + 26 = 360
Simplify further:
9x = 334
Divide both sides by 9:
x = 334 / 9
Now you can find the value of x by dividing 334 by 9, which is approximately 37.111.
For the second situation:
m∠AOB = 4x + 3
m∠BOC = 7x
m∠AOD = 16x - 1
Using the angle addition postulate, the sum of these three angles is equal to 360 degrees:
m∠AOB + m∠BOC + m∠AOD = 360
Substitute the given values into the equation:
(4x + 3) + 7x + (16x - 1) = 360
Combine like terms:
4x + 3 + 7x + 16x - 1 = 360
27x + 2 = 360
Simplify further:
27x = 358
Divide both sides by 27:
x = 358 / 27
Now you can find the value of x by dividing 358 by 27, which is approximately 13.259.