Find the zeros of the function algebraically. (Enter your answers as a comma-separated list.)
f(x) = 3x + 18
f(x) = -5/2 x + 10
however, if you want to go through the math, applicable to more difficult problems,
3x+18 = 0
3(x+6) = 0
Now you have a product whose results is zero. If two numbers multiplied together produce a zero product, then at least one of them must be zero. That is the key to solving these things.
So, either
3 = 0 (sorry, no solution here)
or
x+6 = 0
x = -6
That covers all the possibilities. That is why we factor polynomials and set the product to zero.
f(x) = 3x+27
To find the zeros of the function algebraically, we need to set f(x) equal to zero and solve for x.
Setting f(x) equal to zero, we have:
0 = 3x + 18
To solve for x, we can start by subtracting 18 from both sides of the equation:
-18 = 3x
Next, we divide both sides of the equation by 3 to isolate x:
-6 = x
Therefore, the zero of the function f(x) = 3x + 18 is x = -6.
So, the zeros of the function algebraically are -6.
Clearly your function is a straight line with a slope of 3
So it has one zero.
solve 3x+18 = 0 , etc