What is a counterexample for the conjecture? Conjecture: Any number that is divisible by 6 is also divisible by 12.
3*6 = 18 is not divisible by 12
Why did the number go to the party alone? Because it couldn't find the right multiple to bring along!
But jokes aside, a counterexample for the conjecture that any number divisible by 6 is also divisible by 12 would be the number 6 itself. Since 6 is divisible by 6, but not by 12, it shows that the conjecture is false.
To find a counterexample for the given conjecture, we need to look for a number that is divisible by 6 but not divisible by 12.
Let's start by finding a number that is divisible by 6. One such number is 18, which is divisible by 6 since 18 ÷ 6 = 3.
Now, we need to check if 18 is also divisible by 12. If it is not, then it serves as a counterexample to the conjecture.
To check divisibility by 12, we need to divide 18 by 12. However, since 18 is not divisible by 12, we can conclude that 18 is a counterexample to the conjecture.
Therefore, 18 is a number that is divisible by 6 but not divisible by 12, and it acts as a counterexample to the conjecture.
To find a counterexample for the conjecture, we need to find a number that is divisible by 6 but not divisible by 12.
We know that a number is divisible by 6 if it is divisible by both 2 and 3. However, for a number to be divisible by 12, it needs to be divisible by both 2 and 6.
Let's consider the number 18. It is divisible by 6 (since 6 × 3 = 18), but it is not divisible by 12. When we divide 18 by 12, we get a quotient of 1 with a remainder of 6. Since there is a remainder, we can conclude that 18 is not divisible by 12.
Therefore, 18 serves as a counterexample to the conjecture. It is a number that is divisible by 6 but not divisible by 12.