Given the explicit expression

f(n)=4n+2
, write a set showing the sequence.(1 point)

{2, 6, 10, 14,...}

{6, 8, 10, 12,...}

{4, 8, 12, 16,...}

{6, 10, 14, 18,...} Given the explicit expression
f(n)=5n−2
, write a set showing the sequence, and write a recursive expression. (1 point)

{5, 10, 15, 20,...}
,
f(1)=5
and
f(n)=f(n−1)+5
for
n>1

{5, 10, 15, 20,...}
,
f(1)=5
and
f(n)=f(n−1)+4
for
n>1

{3, 8, 13, 18,...}
,
f(1)=3
and
f(n)=f(n−1)+5
for
n>1

{3, 8, 13, 18,...}
,
f(1)=3
and
f(n)=f(n−1)+4
for
n>1Given the explicit expression
f(n)=2n+6
, which are the seat numbers between and including Sasha and her friend down the aisle? Write a set showing the sequence, and write a recursive expression. What is Sasha's seat number?(1 point)

Her seat number is the first number in the sequence, so
f(1)=2
, which means that her seat number is 2. The set describing the sequence is then
{2, 4, 6, 8,...}
. The recursive formula is given as
f(1)=2
and
f(n)=f(n−1)+2
for
n>1
.

Her seat number is the first number in the sequence, so
f(1)=2
, which means that her seat number is 2. The set describing the sequence is then
{2, 4, 6, 8,...}
. The recursive formula is given as
f(1)=2
and
f(n)=f(n−1)+4
for
n>1
.

Her seat number is the first number in the sequence, so
f(1)=8
, which means that her seat number is 8. The set describing the sequence is then
{8, 10, 12, 14,...}
. The recursive formula is given as
f(1)=8
and
f(n)=f(n−1)+4
for
n>1
.

Her seat number is the first number in the sequence, so
f(1)=8
, which means that her seat number is 8. The set describing the sequence is then
{8, 10, 12, 14,...}
. The recursive formula is given as
f(1)=8
and
f(n)=f(n−1)+2
for
n>1
.Given the explicit expression
f(n)=3n
, write a set showing the sequence. Then, write a recursive expression. (1 point)

{1, 4, 7, 10...}
in which
f(1)=1
and
f(n)=f(n−1)+4
for
n>1

{3, 6, 9, 12...}
in which
f(1)=3
and
f(n)=f(n−1)+3
for
n>1

{4, 7, 10, 13...}
in which
f(1)=4
and
f(n)=f(n−1)+3
for
n>1

{3, 6, 9, 12...}
in which
f(1)=3
and
f(n)=f(n−1)+3
for
n<1Given the explicit expression
f(n)=2n+5
, write a set showing the sequence. Then, write a recursive expression. (1 point)

{7, 9, 11, 13,...}
in which
f(1)=7
and
f(n)=f(n−1)+2
for
n>1

{7, 9, 11, 13,...}
in which
f(1)=7
and
f(n)=f(n+1)−2
for
n>1

{−3, −1, 1, 3,...}
in which
f(1)=−3
and
f(n)=f(n−1)+3
for
n>1

{2, 4, 6, 8,...}
in which
f(1)=2
and
f(n)=f(n−1)+2
for
n>1Given the explicit expression
f(n)=2n+5
, write a set showing the sequence. Then, write a recursive expression. (1 point)

{7, 9, 11, 13,...}
in which
f(1)=7
and
f(n)=f(n−1)+2
for
n>1

{7, 9, 11, 13,...}
in which
f(1)=7
and
f(n)=f(n+1)−2
for
n>1

{−3, −1, 1, 3,...}
in which
f(1)=−3
and
f(n)=f(n−1)+3
for
n>1

{2, 4, 6, 8,...}
in which
f(1)=2
and
f(n)=f(n−1)+2
for
n>1

I assume that I know which lesson this is, Secondary Math unit 3 lesson 11..

1. {6, 10, 14, 18}
2. {3, 8, 13, 18}, f(1) = 3 and f(n)=f(n - 1) + 5 for n > 1
3. Her seat is the first number in the sequence, so f (1) = 8, which means that her seat number is 8. The set describing the sequence is then {8, 10, 12, 14}. The recursive formula is given as f (1) = 8 and f (n) = f (n - 1) + 2 for n > 1.
4.{3, 6, 9, 12} in which f(1) = 3 and f (n) = f(n - 1) +3 for n > 1
5. {7, 9, 11, 13} f(1) =7 and f(n) = f(n - 1) + 2 for n > 1

{7, 9, 11, 13,...}

in which
f(1)=7
and
f(n)=f(n−1)+2
for
n>1

The correct answer is:

Given the explicit expression f(n) = 4n + 2, the set showing the sequence is {2, 6, 10, 14,...}.

Given the explicit expression f(n) = 5n - 2, the set showing the sequence is {3, 8, 13, 18,...}, and the recursive expression is f(1) = 3 and f(n) = f(n-1) + 5 for n > 1.

Given the explicit expression f(n) = 2n + 6, the seat numbers between and including Sasha and her friend down the aisle are {2, 4, 6, 8,...}. Sasha's seat number is the first number in the sequence, which is 2. The recursive expression is f(1) = 2 and f(n) = f(n-1) + 2 for n > 1.

Given the explicit expression f(n) = 3n, the set showing the sequence is {3, 6, 9, 12...}, and the recursive expression is f(1) = 3 and f(n) = f(n-1) + 3 for n > 1.

Given the explicit expression f(n) = 2n + 5, the set showing the sequence is {7, 9, 11, 13,...}, and the recursive expression is f(1) = 7 and f(n) = f(n-1) + 2 for n > 1.

The correct answer is:

Given the explicit expression f(n) = 2n + 5, the set showing the sequence is {7, 9, 11, 13,...}. The first term in the sequence is 7, so f(1) = 7. The recursive expression is f(n) = f(n-1) + 2 for n > 1.

It is not easy to see where one question ends and the next one begins.

You did not indicate which are your choices, so how can we evaluate your work

I will start you on the first one:
f(n)=4n+2
f(1) = 4(1) + 2 = 6
f(2) = 4(2) + 2 = 10
....
Now which choice shows this pattern?

-------
{5, 10, 15, 20,...}
,
f(1)=5
and
f(n)=f(n−1)+5
for
n>1

If this is the third question, you are correct

I will wait for you to separate and number the questions, I don't feel like spending a lot of time
guessing which is a question and which is the answer to a question