A 3L sample of paint that has a density of 5 g/ml is found to contain 10% by mass Pb3N2(s). How many
grams of lead were in the paint sample?
Sidha sidha answer post ni kr skte
Sry to say bt what u wrote it is literally not understable u only know what u wrote
Why did the paint go to therapy? Because it had some unresolved Pb3N2(s) issues!
To calculate the grams of lead in the paint sample, we'll need to find the mass of the entire paint sample first. Since we know the volume of the paint (3L) and its density (5 g/ml), we can calculate the mass using the formula: mass = volume x density.
The mass of the paint sample would be:
mass = 3L x 5 g/ml = 15 g
Now, to find the grams of lead in the paint sample, we need to multiply the mass of the sample by the percentage of lead present (10%).
grams of lead = (10% x 15 g) / 100 = 1.5 g
So, there were 1.5 grams of lead in the paint sample. I bet it made the paint look pretty "lead-tastic"!
1435.3g
To determine the number of grams of lead in the paint sample, we need to use the mass percent composition and the density of the paint.
Step 1: Calculate the mass of the paint sample.
The given volume of the paint sample is 3L, and the density of the paint is 5 g/ml. Therefore, the mass of the paint sample can be found using the formula:
Mass = Volume x Density
Mass = 3L x 5 g/ml = 15g
Step 2: Calculate the mass of the Pb3N2 in the paint sample.
The mass percent of Pb3N2 in the paint sample is given as 10%. This means that 10% of the total mass of the paint is due to Pb3N2.
Mass of Pb3N2 = Mass of the paint sample x Mass percent of Pb3N2
Mass of Pb3N2 = 15g x 0.10 = 1.5g
Therefore, there are 1.5 grams of lead (Pb) in the paint sample.
mass = volume x density.
mass = 3000 mL x 5 g/mL = ? grams paint.
It contains 10% Pb3N2 so ?grams paint x 0.10 = grams Pb3N2.
10% of the 15 kg of paint is Pb3N2
find the percentage (by mass) of Pb in Pb3N2
...multiply the result by 10% and by 15kg