Approximate the irrational number -/8 to two decimals

If that is an attempt at √8, your calculator will show you that

√8 ≈ 2.828427
So round that to two decimal places.

If you don't want to use a calculator, you can always extract the root by hand (google can show you how), or start guessing.
2^2 = 4
3^2 = 9
So you know it will be close to 3
2.8^2 = 7.84
2.9^2 = 8.41
So you can see it will be close to 2.8
2.82^2 = 7.9524
2.83^2 = 8.0089
So it is clearly closer to 2.83 than 2.82

To approximate the irrational number -√8 to two decimal places, you can use a calculator or manually calculate it step-by-step. Here's the step-by-step process:

1. Calculate the square root of 8: √8 ≈ 2.8284271247461903
2. Multiply the result by -1 to get the negative value: -1 * 2.8284271247461903 = -2.8284271247461903
3. Round the result to two decimal places: -2.83

Therefore, the approximate value of -√8 to two decimal places is -2.83.

To approximate the irrational number √8 to two decimal places, follow these steps:

Step 1: Determine the two perfect square numbers between which the irrational number lies. In this case, it is between 2 and 3, since 2² = 4 and 3² = 9.

Step 2: Take the square root of the higher perfect square number. In this case, it is √9, which equals 3.

Step 3: Divide the irrational number by the square root calculated in Step 2. In this case, it is -√8 / 3.

Step 4: Calculate the decimal approximation of the division from Step 3. In this case, it is approximately -2.83.

Therefore, the approximate value of the irrational number -√8 to two decimal places is -2.83.

Please check for typo.