what happens when there is a force of 200n to the right and a force of 100n to the left simultaneously on the cart

A non-zero net force is acing on it

an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force on the x-axis.
Graphs visually show the relationship between the variables under investigation
object changes direction
cart will move right

guaranteed 100%

a nonzero net force is acting one it

an upward sloping line drawn or a graph with acceleration is shown on the y-acid and force is shown on the x-axis

graphs visually show the relationship between the variables under investigation

the object is at rest

the cart will move to the right

The cart will move to the right.

depending on how much it can hold it tips down from the 100 side

sorry I meant 200

Anna is correct

sorry guys i dont know any thing i want to know this answer FIND THE MAGNITUDE OF THE RESULTANT FORCE. 200N ON THE LEFT 100N ON THE RIGHT ..............

When there is a force of 200N to the right and a force of 100N to the left simultaneously on the cart, we need to consider the net force acting on the cart. The net force is the vector sum of all the forces acting on an object.

In this case, the force of 200N to the right and the force of 100N to the left act in opposite directions. To determine the net force, we subtract the magnitude of the force in the opposite direction. Thus, the net force can be calculated as:

Net Force = 200N - 100N

Net Force = 100N to the right

The net force of 100N to the right means that there is an unbalanced force acting on the cart, causing it to move in the direction of the net force. Therefore, the cart will experience an acceleration in the rightward direction.

To summarize, when there is a force of 200N to the right and a force of 100N to the left simultaneously on the cart, the net force acting on the cart is 100N to the right. This net force will cause the cart to accelerate in the rightward direction.

4th one is wrong