In an examination 18 candidates passed mathematics 17 candidates passed physics 11 candidates passed mathematics and physics and 1 failed both subjects
Find the number of candidates that passed mathematics only
The number of candidates that passed physics only
The total number of candidates that sat for the examination
Use Venn diagram.
Start with the intersection, enter 11
math only = 18-11 = 7
physics only = 17-11 = 6
outside both circles: 1
total that sat for the exam = 11+7+6+1 = 25
your turn for the other questions
950 candidates
Please I can't write it much please i beg you please respond i am from lagos
Well, it seems like we have a bunch of candidates who can't keep up with their subjects. Let's do some math comedy to solve the puzzle!
If we call the number of candidates who passed mathematics only as 'M,' the number of candidates who passed physics only as 'P,' and the total number of candidates as 'T,' we have the following information:
M = ?
P = ?
T = ?
Now, let's work with the given information:
- 18 candidates passed mathematics, which means 'M' is at least 18.
- 17 candidates passed physics, so 'P' is at least 17.
- 11 candidates passed both subjects, meaning 'M' and 'P' overlap by 11 students.
But wait! One student failed both subjects, so we need to subtract them from 'M' and 'P':
(M - 1) + (P - 1) + 11 = T
And since we want to find the values of 'M' and 'P,' let's solve this equation with some mathematical humor:
T = (M + P - 2) + 11
Now, let's use the final piece of information: the number of students who sat for the examination. But, hey, that information seems to be missing! It's like the exam paper got lost. Uh-oh, it looks like the joke's on us. Without that information, we can't determine the total number of candidates that sat for the exam.
But fret not, my friend! I hope this mathematical comedy routine at least gave you a chuckle.
To find the number of candidates that passed mathematics only, we need to subtract the number of candidates who passed both mathematics and physics, as well as the number of candidates who passed physics only, from the total number of candidates who passed mathematics.
Let's break down the given information step by step:
- 18 candidates passed mathematics: This includes candidates who passed mathematics only and candidates who passed both mathematics and physics.
- 17 candidates passed physics: This includes candidates who passed physics only and candidates who passed both mathematics and physics.
- 11 candidates passed both mathematics and physics: This includes candidates who passed both subjects.
We can use a mathematical formula called the Principle of Inclusion-Exclusion to find the number of candidates that passed mathematics only.
First, we calculate the total number of candidates who passed mathematics by adding the number of candidates who passed mathematics (18) and the number of candidates who passed both mathematics and physics (11):
Total number of candidates who passed mathematics = 18 + 11 = 29
Next, we subtract the number of candidates who passed both mathematics and physics (11) from the total number of candidates who passed mathematics to find the number of candidates who passed mathematics only:
Number of candidates who passed mathematics only = Total number of candidates who passed mathematics - Number of candidates who passed both mathematics and physics
= 29 - 11 = 18
Therefore, the number of candidates that passed mathematics only is 18.
Now, let's find the number of candidates that passed physics only.
Since we know that 11 candidates passed both mathematics and physics, we need to subtract this number from the total number of candidates who passed physics:
Number of candidates who passed physics only = Total number of candidates who passed physics - Number of candidates who passed both mathematics and physics
= 17 - 11 = 6
Therefore, the number of candidates that passed physics only is 6.
Finally, to find the total number of candidates that sat for the examination, we need to add the number of candidates who passed mathematics only, the number of candidates who passed physics only, and the number of candidates who passed both subjects:
Total number of candidates that sat for the examination = Number of candidates who passed mathematics only + Number of candidates who passed physics only + Number of candidates who passed both mathematics and physics
= 18 + 6 + 11 + 1 (since 1 candidate failed both subjects)
= 36
Therefore, the total number of candidates that sat for the examination is 36.